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2 years ago

10

The current in the wires of a circuit is 90 milliAmps. If the resistance of the circuit were doubled (with no change in voltage)

, then its new current would be _____ milliAmps.

1 answer:

melomori [17]2 years ago

7 0

Answer:

$I = 45mA$

Explanation:

Given

$I = 90mA$ --- Current

Required

Determine the new current when resistance is doubled

Using $V = IR$

Initially, we have:

$V = 90mA * R$

When resistance is doubled and voltage remains unaltered, we have:

$V = I* 2R$

2R represents the new resistance and I represents the new current

Equate both values of V

$90mA * R = I* 2R$

Make I the subject

$I = \frac{90mA * R}{2R}$

$I = \frac{90mA }{2}$

$I = 45mA$

The new current is 45milliAmps

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Answer:

b. Technician B only

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2 years ago

assume a five layer network model. There are 700 bytes of application data. There is a 20 bye header at the transport layer, a 2

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Answer: The overhead percentage is 7.7%.

Explanation:

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2 years ago

Compute the solution to x + 2x + 2x = 0 for Xo = 0 mm, vo = 1 mm/s and write down the closed-form expression for the response.

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Answer:

β = $\frac{c}{\sqrt{km} }$ = 0.7071 ≈ 1 ( damping condition )

closed-form expression for the response is attached below

Explanation:

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computing a solution :

M = 1,

c = 2,

k = 2,

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next we determine the damping condition using the damping formula

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Firefighters are holding a nozzle at the end of a hose while trying to extinguish a fire. The nozzle exit diameter is 8 cm, and

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Question

Determine the average water exit velocity

Answer:

53.05 m/s

Explanation:

Given information

Volume flow rate, $Q=16 m^{3}/min$

Diameter d= 8cm= 0.08 m

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The flow is jet flow hence momentum-flux correction factor is unity
Gravitational force is not considered
The flow is steady, frictionless and incompressible
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2 years ago

An iron-carbon alloy initially containing 0.286 wt% C is exposed to an oxygen-rich and virtually carbon-free atmosphere at 1200°

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Answer:

Explanation:

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