The table and graph below show the distances traveled by two different objects. (3 points)
1 answer:
You might be interested in
Answer:
Radius=15.773 m
Explanation:
Given data
v=29.5 km/h=8.2 m/s
μs=0.435
To find
Radius R
Solution
The acceleration is a centripetal acceleration which is experienced by the bicycle given by
This acceleration is only due to static force which given as
The maximum value of the static force is given as
where
FN is normal force equal to mass*gravity
Therefore when the car is on the verge of sliding
Therefore the minimum radius should be found by the bicycle move without sliding
So
Answer:
A) d = v² / (2g (μ cos θ + syn θ) B) μ = tan θ
Explanation:
Part A
We can work this part with the work and energy theorem, where the work of the friction forces is equal to the energy change of the system.
The work is
W = fr .d
With the force of friction it opposes the movement
W = - fr d
The energy at the lowest point is
Em₀ = K = ½ m v²
The energy at the highest point
= U = m g y
The height (y) can be found by trigonometry
sin θ = y / d
y = d sin θ
W = –Em₀
-fr d = mg d sin θ - ½ m v²
The equation for the force of friction is
fr = μ N
From Newton's second law
N - W cos Te = 0
We replace
-μ (mg cos θ) d - mg d sin θ = - ½ m v²
d g (μ cos θ + sin θ) = ½ v²
d = v² / (2g (μ cos θ + syn θ)
Part B
The block is stopped, what is the Angle tet, let's use Newton's second law
fr - W sin θ = 0 ⇒ fr = W sin θ
N - W cos θ= 0 ⇒ N = w cos θ
fr = μ N
μ (mg cos θ) = mg syn θ
μ = syn θ / cos θ
μ = tan θ