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Rzqust [24]
3 years ago
11

An Olympic diver is on a diving platform 3.80 m above the water. To start her dive, she runs off of the platform with a speed of

1.24 m/s in the horizontal direction. What is the diver's speed just before she enters the water
Physics
1 answer:
AVprozaik [17]3 years ago
3 0

Answer:

the diver's speed just before she enters the water is 8.718 m/s.

Explanation:

Given;

height of the diving platform, h = 3.8 m

initial velocity of the diver, u = 1.24 m/s

the diver's speed just before she enters the water is her final velocity, = v

Apply the following kinematic equation to determine the final velocity of the girl;

v² = u² + 2gh

v² = (1.24)² + 2(9.8 x 3.8)

v² = 76.018

v = √76.018

v = 8.718 m/s

Therefore, the diver's speed just before she enters the water is 8.718 m/s.

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The frequency of the wave is 1\cdot 10^9 Hz

Explanation:

The frequency, the wavelength and the speed of a wave are related by the following equation:

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\lambda is the wavelength

For the radio wave in this problem,

\lambda = 0.3 m

c=300,000,000 m/s = 3\cdot 10^8 m/s

Therefore, the frequency is:

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3 years ago
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Answer:

See below

Explanation:

See attached diagram

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A 100 g cart is moving at 0.5 m/s that collides elastically from a stationary 180 g cart. Final velocity is calculated to be 0.25m/s.

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Collision in which part of the kinetic energy is changed to some other form of energy is inelastic collision.

For an elastic collision, we use the formula,

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