E since its a physical model i.e. you can touch and feel the model :)
Metalloids show both metal and non metal properties
Yes if a molecule with a COOH group is called a carboxylic acid.
hope that helps
First, we write out a balanced equation.
HA <--> H(+) + A(-)
Next, we create an ICE table
HA <--> H+ + A-
[]i 0.40M 0M 0M
Δ[] -x +x +x
[]f 0.40-x x x
Next, we write out the Ka expression.
Ka = [H+][A-]/[HA]
Ka = x*x/(0.40-x)
However, because Ka is less than 10^-3, we can assume the amount of dissociation is negligible. Thus,
Assume 0.40-x ≈ 0.40
Therefore, 1.2x10^-6 = x^2/0.40
Then we solve for the [H+] concentration, or x

x=6.93x10^-4
Next, to find pH we do
pH = -log[H+]
pH = -log[6.93x10^-4]
pH = 3.2
Answer:
3HC2H3O2(aq) + Al(OH)3(aq) --> AI(C2H3O2)3(aq) + 3H2O(l)
Explanation:
HC2H3O2 is the chemical formula for Ethanoic acid which can be written as CH3COOH.
Hence, the balanced equation is stated as 3CH3COOH(aq) + Al(OH)3(aq) --> AI(CH3COO)3(aq) + 3H2O(l)
Acid + base → Salt + Water.
The equation is a neutralization reaction in which the acid, aqeous CH3COOH reacts completely with an appropriate amount of base, aqueous Al(OH)3 to produce salt, aqueous AI(CH3COO)3(aq)
and water, liquid H2O only.
During this reaction, the hydrogen ion, H+, from the Ethanoic acid is neutralized by the hydroxide ion, OH-, from the Aluminum hydroxide to form the water molecule, H2O and aluminium ethanoate.
Thus, it is called a neutralization reaction.