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Anarel [89]
2 years ago
6

PLEASE HELP ASAP!!!!!!!!!!!!!!

Chemistry
1 answer:
Phantasy [73]2 years ago
8 0

Answer:

sorry pic is not working

Explanation:

If you can get it to work i can help

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The air we breathe is not considered by chemists to be an element. why not
ohaa [14]
Because Air itself is not an element. it is made up by different elements such as Oxygen and nitrogen. since its made up of a mix of different elements, its rather a homogeneous mixture :)
7 0
3 years ago
Read 2 more answers
(1 pt) You have 250.0 mL of 0.136 M HCl. Using a volumetric pipet, you take 25.00 mL of that solution, place it in a 100.00 ml v
alexdok [17]

Answer:

0.034M HCl is the concentration of the diluted solution

Explanation:

You take, initially, 25.00mL of the 0.136M HCl. Then, you dilute the solution to 100.00mL. The solution is diluted:

100.00mL / 25.00mL = 4. The solution was diluted 4 times.

That means the concentration of the diluted solution is:

0.136M / 4 =

<h3>0.034M HCl is the concentration of the diluted solution</h3>
7 0
3 years ago
1. element with three occupied energy levels and<br> one valence electron
vfiekz [6]

Answer:

Potassium (K) = (2,8,8,1)

This is the element that has three(3) filled energy level and one valence electron

3 0
2 years ago
BRAINLIESTTT ASAP!!!
mote1985 [20]

Answer:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 4p²

Explanation:

This atom will likely have 4 electron shells denotation of – 2.8.8.4

Orbitals shells show the probability, in space around the nucleus, where to find an electron. It is important to note that the 3rd shell has an additional d orbital (-in addition to s and p). However, because the d orbital has a higher energy state than the 4s and 4p orbitals, the d orbital only fills up when these latter ones are completely filled. In this case, the 4p does not completely fill (hence we don't see the d orbital in the notation).

4 0
2 years ago
Deterioration of buildings, bridges, and other structures through the rusting of iron costs millions of dollars a day. The actua
GrogVix [38]

The value of ∆H when 0.250kg of iron rusts is -1.846 × 10³kJ.

The rust forms when 4.85X10³ kJ of heat is released is 888.916 g.

<h3>Chemical reaction:</h3>

4 Fe + 3O2 ------ 2Fe2O3

∆H = -1.65×10³kJ

A) Given,

mass of iron = 0.250kg = 250 g

<h3>Calculation of number of moles</h3>

moles = given mass/ molar mass

= 250/ 55.85 g/mol.

= 4.476 mol

As we know that,

For the rusting of 4 moles of Fe, ∆H = -1.65×10³kJ

For the rusting of 4.476 moles of Fe ∆H required can be calculated as

-1.65×10³kJ × 4.476 mol/ 4mol

∆H required = -1.846 × 10³kJ

Now,

when 2 mol of Fe2O3 formed, ∆H = - 1.65×10³kJ

It can be said that,

-1.65×10³kJ energy released when 2 mol of Fe2O3 formed

So, -4.6 × 10³kJ energy released when 2 mol of Fe2O3 formed

= 2 × -4.6 × 10³kJ / -1.65×10³kJ

= 5.57 mol of Fe2O3 formed

Now,

mass of Fe2O3 formed = 5.57 mol × 159.59 g/mol

= 888.916 g

Thus, we calculated that the rust forms when 4.85X10³ kJ of heat is released is 888.916 g. and the value of ∆H when 0.250kg of iron rusts is -1.846 × 10³kJ.

learn more about ∆H:

brainly.com/question/24170335

#SPJ4

DISCLAIMER:

The given question is incomplete. Below is the complete question

QUESTION:

Deterioration of buildings, bridges, and other structures through the rusting of iron costs millions of dollars a day. The actual process requires water, but a simplified equation is 4Fe(s) + 3O₂(g) → 2Fe₂O₃(s) ΔH = -1.65×10³kJ

a) What is the ∆H when 0.250kg iron rusts.

(b) How much rust forms when 4.85X10³ kJ of heat is released?

7 0
1 year ago
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