The number of particles= 1.43 x 10²⁴ particles
<h3>Further explanation</h3>
Given
53.2 L volume of gas at STP
Required
The number of particles
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
So mol for 53.2 L :
= 53.2/22.4
= 2.375 moles
1 mol = 6.02 x 10²³ particles (molecules, atoms, ions)
The number of paricles for 2.375 moles gas :
= 2.375 x 6.02 x 10²³
= 1.43 x 10²⁴ particles
