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Anika [276]
3 years ago
15

Can someone put each letter by the correct word for my automotive class !

Engineering
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

L = spindle

M = lower ball joint

part without the letter showing = steering knuckle

Explanation:

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Please answer the following questions.
likoan [24]

Basically, the purposes of digital multimeter are to measure two or more electrical values such as:

principally voltage (volts)

current (Ampere)

resistance (Ohms)

8 0
4 years ago
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The smallest crystal lattice defects is a) cracks b) point defects c) planar defects d) dislocations.
ss7ja [257]

Answer:b) Point defects

Explanation: The point defect is the tiny defect that occurs in the lattice. It usually occurs when there is the atoms or ions missing in the lattice structure that creates a irregularity in the structure.The name point defect itself describes that the occurring defect is having a size of point thus is the smallest defect. Therefore option(b) is the correct option.

8 0
3 years ago
Two gases—neon and air—are expanded from P1 to P2 in a closed-system polytropic process with n = 1.2. _____ produces more work w
Makovka662 [10]

Answer:

Note that Air requires lesser work

Explanation:

Calculate  for general work done

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Calculate for work done of NEON

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See solution attached.

7 0
3 years ago
A manufacturer makes two types of drinking straws: one with a square cross-sectional shape, and the other type the typical round
Harlamova29_29 [7]

Answer:

\frac{Q_{square}}{Q_{circle}} =  0.785  

Explanation:

given data

types of drinking straws

  1. square cross-sectional shape
  2. round shape

solution

we know that both perimeter of the cross section are equal

so we can say that

perimeter of square  = perimeter of circle  

4 × S = π × D

here S is length and D is diameter

S = \frac{\pi D}{4}        ....................1

and

ratio of  flow rate through the square and circle is here

\frac{Q_{square}}{Q_{circle}} = \frac{AV^2}{AV^2}  

\frac{Q_{square}}{Q_{circle}} = \frac{S^2}{\frac{\pi D^2}{4}}  

\frac{Q_{square}}{Q_{circle}} = \frac{(\frac{\pi D}{4})^2}{\frac{\pi D^2}{4}}  

\frac{Q_{square}}{Q_{circle}} = \frac{\pi }{4}  

\frac{Q_{square}}{Q_{circle}} =  0.785  

4 0
4 years ago
Plz help electrical technology
oksano4ka [1.4K]

Answer:

OPTION A,Larger

HOPE IT HELPS

8 0
3 years ago
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