Ask question

Ask question

All categories

3 years ago

15

Can someone put each letter by the correct word for my automotive class !

1 answer:

Oksana_A [137]3 years ago

6 0

Answer:

L = spindle

M = lower ball joint

part without the letter showing = steering knuckle

Explanation:

You might be interested in

If a sky diver decides to jump off a jet in Arkansas

andrew-mc [135]

Answer:

The answer to this question can be defined as follows:

Explanation:

The sky driver began his sky journey from Arkansas, drove across the Tennessee River then landed in North Carolina. He returned to both the north in the very same direction. He began with NC, traveled through Tennessee, eventually lands in Arkansas. But North Carolina has been in the third state on which skydiver was traveling over, and It's also more than 700 miles from Arkansas to the NC.

6 0

3 years ago

Jeff is assembling a rear axle unit. He has all

BartSMP [9]

Answer:

He should read the directions

Explanation:

Reading the directions will tell him what he needs to do in order to assemble the rear axle unit. I hope this helped.

6 0

3 years ago

A 40-kN axial load is applied to a short wooden post that is supported by a concrete footing resting on undisturbed soil. Determ

Alla [95]

Answer:

<em>a. 3.33 MPa</em>

<em>b. 0.276 m^2</em>

<em></em>

Explanation:

The image is attached below.

The load = 40 kN = 40000 N

side length of wooden post L = 120 mm = 0.12 m

side width of the wooden post B = 100 mm = 0.1 m

Area of the beam = L x B = 0.12 x 0.1 = 0.012 m^2

a. <em>Maximum bearing stress of the concrete footing = load/area</em>

max. bearing stress = 40000/0.012 = 3.33 x $10^{6}$ Pa = <em>3.33 MPa</em>

b. If the average bearing stress in the soil is 145 kPa = 145000 Pa

<em>size of the footing will be = load ÷ average bearing stress</em>

size of footing = 40000/145000 ≅<em> 0.276 m^2</em>

4 0

3 years ago

Which of the following would be pictured on a fan motors ladder logic diagram

Ipatiy [6.2K]

Answer:B. two Push-button control

Explanation:

4 0

2 years ago

Purely resistive loads of 24kW, 18kW and 12kW are connected between the neutral and the red, yellow and the blue respectively of

seraphim [82]

Answer:

The phase current in each line conductor are;

$I_{R} = 100.17 < 0A$

$I_{Y} = 75.13< - 120A$

$I_{B} = 50.08$

Explanation:

Given the following data;

Red phase = 24kW,

Yellow phase = 18kW

Blue phase = 12kW

Line voltage = 415V

For a star connected system, we have;

$Phase voltage (V_{p} ) = \frac{Line voltage}{\sqrt{3}}$

$Phase voltage (V_{p} ) = \frac{415}{\sqrt{3}}$

$Phase voltage (V_{p} ) = 239.6V$

The phase sequence for RYB is given by;

$V_{R} = 239.6$

$Phase current (I) = \frac{Phase power}{Phase voltage}$

$Hence, I = \frac{P}{V}$

<em>For the Red phase;</em>

$I_{R} = \frac{24000}{239.6$

$I_{R} = 100.17 < 0A$

<em>For the Yellow phase;</em>

$I_{Y} = \frac{18000}{239.6$

$I_{Y} = 75.13< - 120A$

<em>For the Blue phase;</em>

$I_{B} = \frac{12000}{239.6$

$I_{B} = 50.08$

For the line neutral;

$I_{N} =\sqrt{ (I_{R}^{2} +I_{Y}^{2}+I_{B}^{2}-I_{R}I_{Y}-I_{Y}I_{B}-I_{R}I_{B}$

Substituting we have, $I_{N} = 43.29A$

6 0

3 years ago