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Anika [276]
3 years ago
15

Can someone put each letter by the correct word for my automotive class !

Engineering
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

L = spindle

M = lower ball joint

part without the letter showing = steering knuckle

Explanation:

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El usuario "gedo7" es una máquina?​
castortr0y [4]

Answer:

pon una imagen, lo busco y le pregunto  :D

Explanation:

me das corona xfaaaa  :U

3 0
3 years ago
An alloy fin with a thermal conductivity of 200 W/ሺm ∙ Kሻ has a length of 2.5 cm and a thickness of 3.5 mm. The base of the fin
Svetllana [295]

Answer: heat flux into the fun is 21.714 mW/m^2

Explanation:

Heat flux Q = q/A

q = heat transfer rate W

A = area m^2

q = area * conductivity * temperature gradient

Temperature gradient = difference in temperature of the metal faces divided by the thickness.

Therefore Q = k * ( temp. gradient)

Q = 200 * ((400-20)/3.5*10^-2)

Q = 21714285.71 = 21.714 mW/m^2

Answer 2: convective heat transfer flux between fin and air

is 3800W/m^2

Explanation :

q = hA*(Ts-Ta)

h = convective heat transfer coefficient

Ts = temperature of fin

Ta = temperature of air

Q = q/A

Q = h(Ts-Ta)

Q = 10(400 - 20)

Q = 3800 W/m^2

5 0
4 years ago
A closed, rigid tank fitted with a paddle wheel contains 2.0 kg of air, initially at 200oC, 1 bar. During an interval of 10 minu
RUDIKE [14]

Answer:

T=833.8 °C

Explanation:

Given that

m= 2 kg

T₁=200 °C

time ,t= 10 min = 600 s

Work input = 1 KW

Work input = 1 x 600 KJ=600 KJ

Heat input = 0.5 KW

Q= 05 x 600 = 300 KJ

Gas is ideal gas.

We know that for ideal gas internal energy change given as

ΔU= m Cv ΔT

For air Cv= 0.71 KJ/kgK

From first law of thermodynamics

Q  = ΔU +W

Heat input taken as positive and work in put taken as negative.

300 KJ = - 600 KJ + ΔU

ΔU = 900 KJ

ΔU= m Cv ΔT

900 KJ = 2 x 0.71 x (T- 200 )

T=833.8 °C

So the final temperature is T=833.8 °C

8 0
3 years ago
Random ____ fluctuations in the early universe were stretched by a period of intense inflation, resulting in permanent density f
fgiga [73]

Answer:

Quantum

Explanation:

Appearance of energy particles from any where as allowed by uncertainty principle.

7 0
3 years ago
SAE 30 oil at 60 !F flows through a 2-in.-diameter pipe with a mean velocity of 5 ft/s. Determine the value of the Reynolds numb
8090 [49]

Answer:

Re=185.39

Explanation:

Given that

d= 2 in

We know that

1 in = 0.0254 m

d = 0.0508 m

Velocity V= 5 ft/s

1 ft/s = 0.3048 m/s

V = 1.524 m/s

Lets take Density for oil ,ρ = 910 kg/m³

Dynamic viscosity ,μ = 0.38 Pa.s

We know that Reynolds number given as

Re=\dfrac{\rho V d}{\mu}

Re=\dfrac{910\times 1.524\times 0.0508}{0.38}

Re=185.39

Therefore Reynolds number will be 185.39.

3 0
4 years ago
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