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Naya [18.7K]
3 years ago
8

A 40-kN axial load is applied to a short wooden post that is supported by a concrete footing resting on undisturbed soil. Determ

ine (a) the maximum bearing stress on the concrete footing, (b) the size of the footing for which the average bearing stress in the soil is 145 kPa.

Engineering
1 answer:
Alla [95]3 years ago
4 0

Answer:

<em>a. 3.33 MPa</em>

<em>b. 0.276 m^2</em>

<em></em>

Explanation:

The image is attached below.

The load = 40 kN = 40000 N

side length of wooden post L = 120 mm = 0.12 m

side width of the wooden post B  = 100 mm = 0.1 m

Area of the beam = L x B = 0.12 x 0.1 = 0.012 m^2

a. <em>Maximum bearing stress of the concrete footing = load/area</em>

max. bearing stress = 40000/0.012 = 3.33 x 10^{6} Pa = <em>3.33 MPa</em>

b. If the average bearing stress in the soil is 145 kPa = 145000 Pa

<em>size of the footing will be =  load ÷ average bearing stress</em>

size of footing = 40000/145000 ≅<em> 0.276 m^2</em>

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In order to defend against side channel power analysis, we should: ______________
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3 years ago
A plane, opaque, surface M has the following properties: gray, diffuse, absorptivity = 0.7, surface area = 0.5 m2 , temperature
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Explanation:

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3 years ago
What are the de Broglie frequencies and wavelengths of (a) an electron accelerated to 50 eV (b) a proton accelerated to 100 eV
DaniilM [7]

Answer:

(a) De-Brogie wavelength is 0.173 nm and frequency is 2.42 x 10^16 Hz

(b) De-Brogie wavelength is 2.875 pm and frequency is 4.8 x 10^16 Hz

Explanation:

(a)

First, we need to find velocity of electron. Since, it is accelerated by electric potential. Therefore,

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Now, the de Broglie's wavelength is given as:

λ = h/mv

where,

h = Plank's Constant = 6.626 x 10^(-34) kg.m²/s

Therefore,

λ = (6.626 x 10^(-34) kg.m²/s)/(9.1 x 10^(-31) kg)(4.2 x 10^6 m/s)

<u>λ = 0.173 x 10^(-9) m = 0.173 nm</u>

The frequency is given as:

Frequency = f = v/λ

f = (4.2 x 10^6 m/s)/(0.173 x 10^(-9) m)

<u>f = 2.42 x 10^16 Hz</u>

(b)

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K.E of proton = (1/2)mv² = (100 eV)(1.6 x 10^-19 J/1 eV)

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λ = h/mv

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Frequency = f = v/λ

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6 0
4 years ago
Reference Parameters (returning multiple values): Write a C++ function that converts standard time to military time. Inputs incl
valkas [14]

Answer:

Code is given as below:

Explanation:

#include <iostream>

using namespace std;

//function prototype declaration

void MilitaryTime(int, int, char, int &, int &);

int main()

{

    //declare required variables

    int SHour, SMin, MHour, MMin;

    char AorP;

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    cout<<"Enter hours in standard time : ";

    cin>>SHour;

    //check the hours are valid are not

    while(SHour<0 || SHour>12)

    {

         cout<<"Invalid hours for standard time. "

             <<"Try again..."<<endl;

         cout<<"Enter hours in standard time : ";

         cin>>SHour;

    }

    //promt and read the minutes from the user

    cout<<"Enter minutes in standard time : ";

    cin>>SMin;

    //check the minutes are valid are not

    while(SMin<0 || SMin>59)

    {

         cout<<"Invalid minutes for standard time. "

             <<"Try again..."<<endl;

         cout<<"Enter minutes in standard time : ";

         cin>>SMin;

    }

    //promt and read the am or pm from the user

    cout<<"Enter standard time meridiem (a for AM p for PM): ";

    cin>>AorP;

    //check the meridiem is valid are not

    while(!(AorP=='a' || AorP=='p' || AorP=='A' || AorP=='P'))

    {

         cout<<"Invalid meridiem for standard time. "

             <<"Try again..."<<endl;

         cout<<"Enter standard time meridiem (a for AM p for PM): ";

         cin>>AorP;

    }

    //call function to calculate the military time

    MilitaryTime(SHour, SMin, AorP, MHour, MMin);

    //fill zeros and display standard time

    cout.width(2);

    cout.fill('0');

    cout<<SHour<<":";

    cout.width(2);

    cout.fill('0');

    cout<<SMin;

    if(AorP=='a' || AorP=='A')

         cout<<" am = ";

    else

         cout<<" pm = ";

    //fill zeros and display military time

    cout.width(2);

    cout.fill('0');

    cout<<MHour;

    cout.width(2);

    cout.fill('0');

    cout<<MMin<<endl;

    system("PAUSE");

    return 0;

}

//function to calculate the military time with reference parameters

void MilitaryTime(int SHour, int SMin, char AorP, int &MHour, int &MMin)

{

    //check the meredium is am or pm

    //and calculate hours

    if(AorP=='a' || AorP=='A')

    {

         if(SHour==12)

             MHour = 0;

         else

             MHour = SHour;

    }

    else

         MHour = SHour+12;

    MMin = SMin;

5 0
3 years ago
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