R01= 14.1 Ω
R02= 0.03525Ω
<h3>Calculations and Parameters</h3>
Given:
K= E2/E1 = 120/2400
= 0.5
R1= 0.1 Ω, X1= 0.22Ω
R2= 0.035Ω, X2= 0.012Ω
The equivalence resistance as referred to both primary and secondary,
R01= R1 + R2
= R1 + R2/K2
= 0.1 + (0.035/9(0.05)^2)
= 14.1 Ω
R02= R2 + R1
=R2 + K^2.R1
= 0.035 + (0.05)^2 * 0.1
= 0.03525Ω
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Answer:
Go to explaination for the details of the answer.
Explanation:
In order to determine the lifetime (75 years) chronic daily exposure for each individual, we have to first state the terms of our equation:
CDI = Chronic Daily Intake
C= Chemical concentration
CR= Contact Rate
EFD= Exposure Frequency and Distribution
BW= Body Weight
AT = Average Time.
Having names our variables lets create the equations that will be used to derive our answers.
Please kindly check attachment for details of the answer.
Answer:
Multiplying impulse response by t ( option D )
Explanation:
We can obtain The impulse response of strength 1 considering a unit step response by Multiplying impulse response by t .
When we consider the Laplace Domain, and the relationship between unit step and impulse, we can deduce that the Impulse response will take the inverse Laplace transform of the function ( transfer ) . Hence Multiplying impulse response by t will be used .
Answer:
One of the most common injuries that result from working on a scaffold is electrocution. If workers make contact with those wires while working, it can lead to electric shock, especially if that contact damages the wire or if the scaffold is made of metal.