Answer:
The current across the resistance is 0.011 A.
Explanation:
Total resistance, R = 25 ohms
Total current, I = 100 mA = 0.1 A
Let the voltage is V.
By the Ohm's law
V = I R
V = 0.1 x 25 = 2.5 V
Now the resistance is R' = 220 ohm
As they are in parallel so the voltage is same. Let the current is I'.
V = I' x R'
2.5 = I' x 220
I' = 0.011 A
The terminal speed of the marble is 0.588 m/s.
Given:
We know that,
F = mg ......(1)
where,
F = force
m = mass
g = acceleration due to gravity
Also,
v = F/k ......(2)
where,
v = terminal speed
k = proportionality constant
Substituting the value of F from equation (1) in equation (2)
v = mg/k .......(3)
Given,
m = 30 g = 0.030 kg
k = 0.500 kg/s
g = 9.8 m/s²
To find,
v =?
Put the values in equation (3)
v = mg/k
v = 0.03(9.8)/ 0.500
= 0.294/0.500
= 0.588 m/s
Learn more about the calculation of force, refer to:
brainly.com/question/15562875
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The angular velocity, ω=
2π/t; t = 24 hrs = 24 x 3600 seconds = 86400 s
ω = 7.27 x 10⁻⁵
v = ωr
= 7.27 x 10⁻⁵ x 3242.8 x 1.6 x 1000 (converting miles to meters)
= 377.2 m/s
Answer:
b) the potential difference across each is the same.
Explanation:
When resistors are connected in parallel with each other
then the terminals of all the resistors will connected across the terminals of the battery
So we know the potential difference of the battery is same across all the resistors
So we can say that the equivalent resistance of all the resistance is

so its not the mean of all resistors
also we know that the resistance are all different so power across each resistance is different given as

also current in each resistance is also different and given by

so correct answer will be
b) the potential difference across each is the same.
Answer:
A. The energy is not truly lost: it transforms into forms that are not easily put to use.
Explanation:
This is due to the fact that when we use energy, it seems to have disappear, but it really hasn't. In fact, when we use energy, it is changing into another form that has to be converted in order for energy to be present once again.