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3 years ago

Can anybody answer this question. Please...

Physics

1 answer:

Nady [450]3 years ago

8 0

Yes they acquire both poles. Each side facing each other should be opposites
So A is N
C is S
D is N
B is S

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find the resultant in the x-direction , Rx and y-direction , Ry for F1 = 2.5n in the positive x-direction f2 = 1n in the negativ

Advocard [28]

The resultant in the x-direction:

Rx = F1 + F2 = 2.5 N - 1 N = 1.5 N .

The resultant in the y-direction:

Ry = F3 + F4 = 2 N - 3 N = -1 N.

5 0

3 years ago

Water flows past a flat plate that is oriented parallel to the flow with an upstream velocity of 0.4 m/s. (a) Determine the appr

Trava [24]

Answer:

1.12 m

0.08291 m

Explanation:

u = Upstream velocity = 0.4 m/s

Re = Reynold's number = $5\times 10^5$ (turbulent)

$\nu$ = Viscosity of water = $1.12\times 10^{-6}\ Pas$

Here the flow is turbulent so we have the relation

$Re_{xcr}=\frac{ux_{cr}}{\nu}\\\Rightarrow x_{cr}=\frac{Re_{xcr}\nu}{u}\\\Rightarrow x_{cr}=\frac{5\times 10^5\times 1.12\times 10^{-6}}{0.4}\\\Rightarrow x_{cr}=1.4\ m$

The approximate location downstream from the leading edge where the boundary layer becomes turbulent is 1.4 m

Boundary layer thickness relation is given by

$\delta={\frac{\nu x}{u}}^{\frac{1}{5}}\\\Rightarrow \delta={\frac{1.12\times 10^{-6}\times 1.4}{0.4}}^{\frac{1}{5}}\\\Rightarrow \delta=0.08291\ m$

The boundary layer thickness is 0.08291 m

4 0

4 years ago

HEY CAN ANYONE ANSWER DIS QUESTION PLS!!!!!!!!

Valentin [98]

It’s very big and very small numbers

6 0

4 years ago

How long does it take a car travelling at 80 m/s to decelerate to 18 m/s with an acceleration rate of -16m/s?

sertanlavr [38]

initial velocity=u=80m/s
Final velocity=v=18m/s
Acceleration=a=-16m/s^2
Time=t

We know

$\boxed{\sf a=\dfrac{v-u}{t}}$

$\\ \sf\longmapsto t=\dfrac{v-u}{a}$

$\\ \sf\longmapsto t=\dfrac{18-80}{-16}$

$\\ \sf\longmapsto t=\dfrac{-62}{16}$

$\\ \sf\longmapsto t=3.8s$

4 0

3 years ago

A light source emits light with dominant wavelengths in the range of 650 to 690 nm. what is the principle color of light emitted

dsp73

Answer:

Please see below as the answer is self-explanatory.

Explanation:

The visible range extends roughly from 400 nm (violet) to 700 nm (red).
Below the violet is the ultra-violet spectrum (with higher energy) and above red, we have the infra-red spectrum.
The wavelengths in the range of 650 to 690 nm have red as the dominant color.

6 0

3 years ago