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Luba_88 [7]
2 years ago
14

How many atoms are in a 1.8 mol sample of Magnesium (Mg)?

Chemistry
2 answers:
Gnom [1K]2 years ago
5 0

Answer:

1.1 × 10²⁴ atoms Mg

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

[Given] 1.8 mol Mg

[Solve] atoms Mg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 1.8 \ mol \ Mg(\frac{6.022 \cdot 10^{23} \ atoms \ Mg}{1 \ mol \ Mg})
  2. [DA] Multiply [Cancel out units]:                                                                      \displaystyle 1.08396 \cdot 10^{24} \ atoms \ Mg

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.08396 × 10²⁴ atoms Mg ≈ 1.1 × 10²⁴ atoms Mg

scoundrel [369]2 years ago
5 0

Answer:  1.0836 * 10^24 atoms

This value is approximate

===========================================================

Explanation:

1 mole = 6.02*10^23 atoms approximately

This applies to any element.

Multiply both sides by 1.8 and we get...

1 mole = 6.02*10^23 atoms

1.8*1 mole = 1.8*6.02*10^23 atoms

1.8 mole = 10.836*10^23 atoms

1.8 mole = (1.0836*10)*10^23 atoms

1.8 mole = 1.0836 * 10^(1+23)

1.8 mole = 1.0836 * 10^24 atoms

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The two naturally occurring isotopes of antimony, 121Sb (57.21 percent) and 123Sb (42.79 percent), have masses of 120.904 and 12
Alex

Answer:

The correct answer is option c.

Explanation:

Formula used to determine an average atomic mass :

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

Mass of isotope Sb-121 = 120.904 amu

Fractional abundance of Sb-121 = 57.21% = 0.5721

Mass of isotope Sb-123 = 122.904 amu

Fractional abundance of Sb-123 = 42.79% = 0.4279

Average atomic mass of Sb:

120.904 amu\times 0.5721+ 122.904 amu\times 0.4279=121.7598 amu \approx 121.76 amu

7 0
2 years ago
How many moles of carbonate are there in sodium carbonate​
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There are 0.566 moles of carbonate in sodium carbonate.

<h3>CALCULATE MOLES:</h3>
  • The number of moles of carbonate (CO3) in sodium carbonate (Na2CO3) can be calculated by dividing the mass of carbonate in the compound by the molar mass of the compound.

  • no. of moles of CO3 = mass of CO3 ÷ molar mass of Na2CO3

  • Molar mass of Na2CO3 = 23(2) + 12 + 16(3)

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Learn more about number of moles at: brainly.com/question/1542846

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Answer:

Laboratories use both distilled water and deionized water as controls in experiments. Deionization removes only non-charged organic matter from the water.

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