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artcher [175]
3 years ago
10

How many grams of butane (C H20) must be burned in an excess of O, to produce 15.0

Chemistry
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

Mass of butane = 1.87 g

Explanation:

Form a balanced chemical equation for the reaction stated:

C₄H₁₀ + 13/2 O₂ → 4CO₂ + 5H₂O

Number of moles of CO₂

=  \frac{mass}{molar \: mass}

=  \frac{15}{12 + 2(16)}

= 0.34 \: mol

From the equation,

1 mol C₄H₁₀ : 4 mol CO₂

0.085 mol C₄H₁₀ : 0.34 mol CO₂

Mass of butane

= number \: of \: moles \times molar \: mass

= 0.085 \times (12 + 10(1))

= 1.87 \: g

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