Answer:
Explanation:
Given parameters:
Mass of aluminium oxide = 3.87g
Mass of water = 5.67g
Unknown:
Limiting reactant = ?
Solution:
The limiting reactant is the reactant in short supply in a chemical reaction. We need to first write the chemical equation and convert the masses given to the number of moles.
Using the number of moles, we can ascertain the limiting reactants;
Al₂O₃ + 3H₂O → 2Al(OH)₃
Number of moles;
Number of moles = ![\frac{mass}{molar mass}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D)
molar mass of Al₂O₃ = (2x27) + 3(16) = 102g/mole
number of moles =
= 0.04mole
molar mass of H₂O = 2(1) + 16 = 18g/mole
number of moles =
= 0.32mole
From the reaction equation;
1 mole of Al₂O₃ reacted with 3 moles of H₂O
0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O
But we were given 0.32 mole of H₂O and this is in excess of amount required.
This shows that Al₂O₃ is the limiting reactant
The two notations that represent isotopes of the same element is the one that represented in option 1
The lower number is the number of protons while the upper number is the atomic weight
hope this helps
Answer:
0.24 g
Explanation:
Given that:
The average number of the calories for the carbohydrates = 4.1 calorie / g
Also,
6 - oz serving of the diet soda contains less than 1 calorie per can
So,
Maximum mass of carbohydrate = Maximum calorie / Average number of the calories for the carbohydrates
The maximum of the calorie can be 1 calorie per can
So,
<u>Maximum mass of carbohydrate = 1 calorie / 4.1 calorie / g = 0.24 g</u>
Answer:
The new force will be \frac{1}{100} of the original force.
Explanation:
In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.
That said, let's say that our equation for the initial force is:
![F = G\frac{m_1m_2}{R^2}The problem states that the distance decrease to 1/10 of the original distance, this means:[tex]R_2 = \frac{1}{10}R](https://tex.z-dn.net/?f=F%20%3D%20G%5Cfrac%7Bm_1m_2%7D%7BR%5E2%7D%3C%2Fp%3E%3Cp%3EThe%20problem%20states%20%20that%20%20the%20distance%20decrease%20to%201%2F10%20of%20the%20original%20distance%2C%20this%20means%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DR_2%20%3D%20%5Cfrac%7B1%7D%7B10%7DR)
And the force at this distance would be written in terms of the same equation:
![F_2 = G\frac{m_1m_2}{R_2^2}](https://tex.z-dn.net/?f=F_2%20%3D%20G%5Cfrac%7Bm_1m_2%7D%7BR_2%5E2%7D)
Find the ratio between the final and the initial force:
![\frac{F_2}{F} = \frac{G\frac{m_1m_2}{R_2^2}}{G\frac{m_1m_2}{R^2}}](https://tex.z-dn.net/?f=%5Cfrac%7BF_2%7D%7BF%7D%20%3D%20%5Cfrac%7BG%5Cfrac%7Bm_1m_2%7D%7BR_2%5E2%7D%7D%7BG%5Cfrac%7Bm_1m_2%7D%7BR%5E2%7D%7D)
Substitute the value for the final distance in terms of the initial distance:
![\frac{F_2}{F} = \frac{G\frac{m_1m_2}{(\frac{R}{10})^2}}{G\frac{m_1m_2}{R^2}}](https://tex.z-dn.net/?f=%5Cfrac%7BF_2%7D%7BF%7D%20%3D%20%5Cfrac%7BG%5Cfrac%7Bm_1m_2%7D%7B%28%5Cfrac%7BR%7D%7B10%7D%29%5E2%7D%7D%7BG%5Cfrac%7Bm_1m_2%7D%7BR%5E2%7D%7D)
Simplify:
![\frac{F_2}{F} = \frac{\frac{1}{100R^2}}{\frac{1}{R^2}}=\frac{1}{100}](https://tex.z-dn.net/?f=%5Cfrac%7BF_2%7D%7BF%7D%20%3D%20%5Cfrac%7B%5Cfrac%7B1%7D%7B100R%5E2%7D%7D%7B%5Cfrac%7B1%7D%7BR%5E2%7D%7D%3D%5Cfrac%7B1%7D%7B100%7D)
This means the new force will be \frac{1}{100} of the original force.
Chlorine is more reactive than argon, because argon is not reactive at all. Chlorine only has to gain 1 valence electron