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Svet_ta [14]
3 years ago
7

the temperature of a bowl of hot soup goes down after the soup is poured into a bowl. whats happening to the motion of the parti

cles as it cools
Physics
1 answer:
Stels [109]3 years ago
6 0

Given what we know, as with all substances, the particles in the bowl of hot soup will slow down as they cool after being poured.

<h3>Why do particles slow when cooled?</h3>
  • This has to do with energy.
  • The soup particles are excited by heat energy.
  • As the soup is poured, its heat energy radiates and it loses energy.
  • Decreased energy causes the particles to slow down.

Therefore, the motion of the particles of the soup decrease or slows down as the soup cools due to the loss of energy they are experiencing. The soup radiates heat energy into the room or plate, causing the particles to lose energy and slow down.

To learn more about heat energy visit:

brainly.com/question/1495272?referrer=searchResults

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A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.9 rad/s in 3.10 s. (a) F
Mademuasel [1]

Answer:

The value is  \alpha  = 3.84 \  rad/s^2

Explanation:

From the question we are told that

    The constant angular speed is  w =  11.9 \  rad/s

     The time taken is  t =  3.10 \  s

Generally the magnitude of the angular acceleration is  mathematically represented as  

          \alpha  = \frac{w}{t}

=>     \alpha  = \frac{11.9}{ 3.10 }

=>     \alpha  = 3.84 \  rad/s^2

7 0
3 years ago
An object has 16 N of force being applied to the right, 16 N of force being applied to the left, and 6 N of force being applied
umka2103 [35]

Answer:

the net force on the object is 6 N.

Explanation:

Given;

force applied to the right on the object, F_r = 16 N

force applied to the left of the object, F_l = 16 N

force applied downward on the object, F_d = 6 N

The net horizontal force on the object = F_r - F_l = 16N -16N = 0

The net vertical force on the object = 6 \ N \ downward

The net force on the object is calculated as;

F_{net}^2 = 6^2 + 0\\\\F_{net}^2 = 36\\\\F_{net} = \sqrt{36} \\\\F_{net} = 6 \ N

Therefore, the net force on the object is 6 N.

7 0
3 years ago
PART ONE
GenaCL600 [577]

Answer:

1. F = 45,458.17 N

2. P = 12,800,000 W

Explanation:

Part 1. The thrust force is the sum of the forces on the air and on the fuel.

For the air, 107 kg of air is accelerated from 281 m/s to 679 m/s in 1 second.

F = ma

F = (107 kg) (679 m/s − 281 m/s) / (1 s)

F = 42,586 N

For the fuel, 4.23 kg of fuel is accelerated from 0 m/s to 679 m/s in 1 second.

F = ma

F = (4.23 kg) (679 m/s − 0 m/s) / (1 s)

F = 2,872.17 N

So the thrust on the jet is:

F = 42,586 N + 2,872.17 N

F = 45,458.17 N

Rounded to three significant figures, the force is 45,500 N.

Part 2. Power = work / time, and work = force × distance, so:

Power = force × distance / time

Power = force × velocity

P = (45,458.17 N) (281 m/s)

P = 12,773,745.77 W

Rounded to three significant figures, the power is 12,800,000 W.

7 0
3 years ago
Describe how humans’ actions and natural processes have modified coastal regions in Louisiana and other locations
il63 [147K]
Coastal erosion has depleted a large portion of South Louisiana's wetlands along the coastline in swamps and marshes mainly due to storm surges. But other factors also contributed to this erosion. Canals and waterways dug through the marshes and swamps for the oil industry is one factor. Man-made levees erected to provide protection to residents living adjacent to the river is another major cause. Large scale logging especially in the early 1900's also damaged the wetlands.
3 0
4 years ago
What average net force is required to accelerate a 9.5 g
Nesterboy [21]

Answer:

2361 Newtons

Explanation:

From the second Newton's law of motion;

F = ma

In this case;

we are given;

Mass as 9.5 g

Initial speed as 0 m/s

Final velocity as 650 m/s

Distance is 0.85 m

Using the equation;

V² = U² + 2as

But u = 0

v² = 2as

Therefore;

a = v² ÷ 2s

  = 650² ÷ 2(0.85)

  = 248,529.40 m/s²

But;

F = ma

   = 0.0095 kg × 248,529.40 m/s²

   = 2361 Newtons

Therefore;

The average net force required to accelerate the bullet is 2361 Newtons.

6 0
3 years ago
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