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3 years ago

How would the moon appear from Earth if the moon did not rotate?

2 answers:

andrey2020 [161]3 years ago

6 0

It would mean that only one side of earth would be light and the other dark all the time also we would only see the sun on one side and on the other we see the moon

n200080 [17]3 years ago

4 0

As the Earth rotates, the Moon rotates the same, hence why we only see one side of the Moon at any time, but if it stopped rotating we would see different parts of it as we rotate...basically it wouldn't look the same all the time (source: my brain, or 7th grade science class: either or)

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A 40.0 kg wagon is towed up a hill inclined at 18.5 degrees with respect to the horizontal. The tow rope is parallel to the incl

sp2606 [1]

Answer:

7.9m/s

Explanation:

We are given that

Mass of wagon=40 kg

$\theta=18.5^{\circ}$

Tension= $140 N$

Initial velocity of wagon= $u=0$

Displacement=s=80 m

Net force applied on wagon= $F=T-mgsin\theta=140-40(9.8)sin18.5=15.7 N$

By using $g=9.8m/s^2$

$a=\frac{F}{a}=\frac{15.7}{40}=0.39m/s^2$

We know that

$v^2-u^2=2as$

Using the formula

$v^2=2\times 0.39\times 80$

$v=\sqrt{2\times 0.39\times 80}=7.9m/s$

5 0

3 years ago

Where are the nodules of a legume found?

Sveta_85 [38]

Answer:

The answer is roots.

Explanation:

Root nodules are found on the <em>roots of plants</em>, primarily legumes, that form a symbiosis with nitrogen-fixing bacteria. so it is roots

6 0

3 years ago

HELP ASAPPP PLZZZ I HAVE A TIMER WILL GIVE YOU THE 30 POINTS

trapecia [35]

It holds the atoms together (aka your last option)

8 0

3 years ago

An oscillating block - spring system has a mechanical energy of 1.10 j, and amplitude of 11.0 cm, and a maximum speed of 1.7 m/s

ioda

The total mechanical energy of the block-spring system is given by the sum of the potential energy and the kinetic energy of the block:
$E=U+K= \frac{1}{2}kx^2 + \frac{1}{2}mv^2$
where
k is the spring constant
x is the elongation/compression of the spring
m is the mass of the block
v is the speed of the block

At the point of maximum displacement of the spring, the velocity of the block is zero: v=0, so the kinetic energy is zero and the mechanical energy is just potential energy of the spring:
$E= \frac{1}{2}kA^2$ (1)
where we used x=A, the amplitude (which is the maximum displacement of the spring).
Since we know
A = 11.0 cm= 0.11 m
E = 1.10 J
We can re-arrange (1) to find the spring constant:
$k= \frac{2E}{A^2} = \frac{2 \cdot 1.10 J}{(0.11 m)^2}=181.8 N/m$

3 0

2 years ago

Which statement correctly describes variable stars?

Kryger [21]

Answer:

Explanation:

The Period-Luminosity relationship tells us that luminosity increases with the period, and of course the more luminosity a star has the more far away they can be seen, so from this we know that:

A) False since lower luminosities can be observed when they are close.

B) False since longer periods means higher luminosities

C) False since lower luminosities can be observed when they are close.

D) True: Variable stars with shorter periods have lower luminosities, so they can only be observed when they are close.

5 0

3 years ago