1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
faust18 [17]
3 years ago
9

I need help, please!

Physics
1 answer:
marta [7]3 years ago
7 0

NO. it is not balanced

You might be interested in
Even when the head is held erect, as in the figure below, its center of mass is not directly over the principal point of support
alexandr1967 [171]

We are asked to determine the force required by the neck muscle in order to keep the head in equilibrium. To do that we will add the torques produced by the muscle force and the weight of the head. We will use torque in the clockwise direction to be negative, therefore, we have:

\Sigma T=r_{M\perp}(F_M)-r_{W\perp}(W)

Since we want to determine the forces when the system is at equilibrium this means that the total sum of torque is zero:

r_{M\perp}(F_M)-r_{W\perp}(W)=0

Now, we solve for the force of the muscle. First, we add the torque of the weight to both sides:

r_{M\perp}(F_M)=r_{W\perp}(W)

Now, we divide by the distance of the muscle:

(F_M)=\frac{r_{W\perp}(W)}{r_{M\perp}}

Now, we substitute the values:

F_M=\frac{(2.4cm)(50N)}{5.1cm}

Now, we solve the operations:

F_M=23.53N

Therefore, the force exerted by the muscles is 23.53 Newtons.

Part B. To determine the force on the pivot we will add the forces we add the vertical forces:

\Sigma F_v=F_j-F_M-W

Since there is no vertical movement the sum of vertical forces is zero:

F_j-F_M-W=0

Now, we add the force of the muscle and the weight to both sides to solve for the force on the pivot:

F_j=F_M+W

Now, we plug in the values:

F_j=23.53N+50N

Solving the operations:

F_j=73.53N

Therefore, the force is 73.53 Newtons.

8 0
1 year ago
Two forces are acting on an object, but the net force on the object in 0n. For the net force to be 0n, all the forces acting on
s344n2d4d5 [400]

The forces acting on the book (Fn and Fg) are equal. Therefore, the netforce is zero and it is an unbalanced force.

8 0
4 years ago
A 2.00 kg, frictionless block s attached to an ideal spring with force constant 550 N/m. At t = 0 the spring is neither stretche
gladu [14]

Answer:

a)    A = 0.603 m , b) a = 165.8 m / s² , c)  F = 331.7 N

Explanation:

For this exercise we use the law of conservation of energy

Starting point before touching the spring

    Em₀ = K = ½ m v²

End Point with fully compressed spring

    Em_{f} = K_{e} = ½ k x²

    Emo = Em_{f}

    ½ m v² = ½ k x²

    x = √(m / k)    v

    x = √ (2.00 / 550)   10.0

    x = 0.603 m

This is the maximum compression corresponding to the range of motion

     A = 0.603 m

b) Let's write Newton's second law at the point of maximum compression

    F = m a

    k x = ma

    a = k / m x

    a = 550 / 2.00 0.603

    a = 165.8 m / s²

With direction to the right (positive)

c) The value of the elastic force, let's calculate

    F = k x

    F = 550 0.603

   F = 331.65 N

5 0
3 years ago
While the change in blank will remain the same during a collision, the force needed to bring an object to a stop can be blank if
Ahat [919]

Explanation :

There are two types of collision i.e. elastic and elastic collision.

  • Elastic collision : In this type of collision, the total momentum and the kinetic energy of the particles remains constant.
  • Inelastic collision : In this type of collision, only the momentum remains constant while there is some loss of kinetic energy occurs.

From Newton's second law,

F = m a

a is the rate of change of velocity.

F=m\dfrac{v}{t}

There is a inverse relation between the force and the time of collision.

The change in <em><u>momentum</u></em> will remain the same during a collision, the force needed to bring an object to a stop can be <em><u>increased</u></em> if the time of the collision is <u><em>decreased</em></u>.

6 0
3 years ago
Read 2 more answers
Two protons in a molecule are 4.40 10-10 m apart. Find the electric force exerted by one proton on the other.
Akimi4 [234]

Answer:

F = 1.19 x 10⁹ N

Explanation:

The electrostatic force between the charged particles is given by Colomb's Law as follows:

F = \frac{kq_{1}q_{2}}{r^{2}}

where,

F = Electrostatic force = ?

k = Colomb's constant = 9 x 10⁹ N.m²/C²

q₁ = q₂ = charge on proton = 1.6 x 10⁻¹⁹ C

r = distance between protons = 4.4 x 10⁻¹⁰ m

Therefore,

F = \frac{(9\ x\ 10^{9}\ Nm^{2}/C^{2})(1.6\ x\ 10^{-19}\ C)(1.6\ x\ 10^{-19}\ C)}{(4.4\ x\ 10^{-10})^{2}} \\\\

<u>F = 1.19 x 10⁹ N</u>

8 0
3 years ago
Other questions:
  • An element's atomic number is 117. How many protons would an atom of this element have?    
    5·1 answer
  • In a parallel circuit with a 4 ohm and a 2 ohm resistor and a 12 volt source, what is the potential difference across the 4 ohm
    14·2 answers
  • 5.Imagine you are ice skating with your BFF. Both of you at rest, when you shove him/her away from you. You have a mass of 65 kg
    8·2 answers
  • A 0.300 kg potato is tied to a string with length 2.30 m , and the other end of the string is tied to a rigid support. The potat
    14·1 answer
  • Dacia wants to know how to determine the polar coordinate θ. What should Katarina tell Dacia?
    10·1 answer
  • A sound wave with a frequency of 510 Hz and a wavelength of 3.5 m is directed toward the bottom of a lake to measure its depth.
    10·1 answer
  • Bob’s wife is in her third trimester of pregnancy. Bob’s _________ is/are likely to affect the health of his unborn baby.
    12·1 answer
  • Please select the word from the list that best fits the definition
    14·1 answer
  • The speed of a rocket just after being launched is 12 m / s.
    15·1 answer
  • How do i exist (serious question, i'm in the dark abyss of nothing please help)
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!