4.) The diagram to the right is the orbit of a comet:

During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 4.02 s, how high above the point where i

alukav5142 [94]

Answer:

d = 19.796m

Explanation:

Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.

So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.

Next, you look for a kinematic equation that has these parameters and the one you should choose is:

$d=vt+\frac{1}{2}at^2$

Now by substituting values in, we get

$d=(0\frac{m}{s})*(2.01s)+\frac{1}{2}(9.8\frac{m}{s^2})(2.01)^2$

d = 19.796m

7 0

3 years ago

explain how a maglev train provides evidence that magnetic fields can apply forces between objects that do not touch.

Furkat [3]

Answer:

Powerful electromagnets are fitted on top of guideways either ttract or repel the magents fitted on the bottom of train. The froce of attraction/repulsion rasies the train in hovering position.

Explanation:

Magentic fields exist between two opposite/like poles. The poles do not have to be touching each other. They can be separated by a distance in a medium that doesn' block magnetic field.

In magelv train the magnetic forces between two poles are used to operate the train. The two poles are separated by train body and air.

4 0

3 years ago

A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What

Sedbober [7]

Answer:

377 nm

Explanation:

Number of lines per meter is, $N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}$

Grating element is, $d=\frac{1}{N}$

$=1.8868 \times 10^{-6} \mathrm{~m}[tex]
Order is, n=5
Condition for maximum intensity is, [tex]d \sin \theta=n \lambda$

$\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\
&=0.377 \times 10^{-6} \mathrm{~m} \\
&=377 \mathrm{~nm}$

7 0

3 years ago

A genetics tool that uses letters to represent dominant and recessive alleles

Studentka2010 [4]

its an punnent square

7 0

3 years ago

A rocket sled with an initial mass of 3 metric tons, invluding 1 ton of fuel, rests on a level section of track. At t=0, the sol

Katena32 [7]

Answer:

v = 719.2 m / s and a = 83.33 m / s²

Explanation:

This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is

v - v₀ = $v_{e}$ ln (M₀ / M)

where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket

In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s

m_fuel = 75 10

m_fuel = 750 kg

As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is

M = 3000 -750 = 2250 kg

let's calculate

v - 0 = 2500 ln (3000/2250)

v = 719.2 m / s

To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is

Push = v_{e} dM / dt

let's calculate

Push = 2500 75

Push = 187500 N

If we use Newton's second law

F = m a

a = F / m

let's calculate

a = 187500/2250

a = 83.33 m / s²

7 0

3 years ago