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Reptile [31]
3 years ago
5

The dosage for an antibiotic is prescribed at 6.0 mg per kilogram of body weight, taken twice daily for two weeks. What total ma

ss of antibiotic will be taken by a 160-lb person for the two-week period? (1 lb = 454 g)
Chemistry
1 answer:
Lelechka [254]3 years ago
5 0

Answer:

12,096 mg of antibiotics

Explanation:

cuz honeyyy:

160lb=72 kg

6mg twice a day so daily 12mg

12mg per kg so 12×72 =864

for 14 days is :864×14=12,096

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What is the limiting reactant in a reaction where 10.0 mol of iron is treated with 12.0 mol of bromine? The product that forms i
hammer [34]

<u>Answer:</u> The limiting reagent in the reaction is bromine.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

Given values:

Moles of iron = 10.0 moles

Moles of bromine = 12.0 moles

The chemical equation for the reaction of iron and bromine follows:

2Fe+3Br_2\rightarrow 2FeBr_3

By the stoichiometry of the reaction:

If 3 moles of bromine reacts with 2 moles of iron

So, 12.0 moles of bromine will react with = \frac{2}{3}\times 12.0=8moles of iron

As the given amount of iron is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Hence, bromine is considered a limiting reagent because it limits the formation of the product.

Thus, the limiting reagent in the reaction is bromine.

3 0
3 years ago
Which of the following is the most reliable prediction about the future of some nonrenewable energy resources?
marishachu [46]

Answer:

hola

Explanation:

7 0
3 years ago
Read 2 more answers
The energy of a photon needed to cause ejection of an electron from a photoemissive metal is expressed as the sum of the binding
slega [8]

Answer:

Binding\ energy=43.43\times 10^{-20}\ J

Explanation:

Using the expression for the photoelectric effect as:

E=h\nu_0+\frac {1}{2}\times m\times v^2

Also, E=\frac {h\times c}{\lambda}

\nu_0=\frac {c}{\lambda_0}

Applying the equation as:

\frac {h\times c}{\lambda}=\frac {hc}{\lambda_0}+\frac {1}{2}\times m\times v^2

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light being bombarded

Given, \lambda=4.00\times 10^{-7}\ m

\frac {hc}{\lambda_0} is the binding energy or threshold energy

\frac {1}{2}\times m\times v^2 is the kinetic energy of the electron emitted.  = 6.26\times 10^{-20}\ J

Thus, applying values as:

\frac{h\times c}{\lambda}=Binding\ Energy+Kinetic\ Energy

\frac{6.626\times 10^{-34}\times 3\times 10^8}{4.00\times 10^{-7}}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

\frac{19.878}{10^{19}\times \:4}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

49.69\times 10^{-20}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

Binding\ energy=43.43\times 10^{-20}\ J

5 0
3 years ago
Chemical equations consist of the chemical formulas of the reactants on the right
Dahasolnce [82]
False. Chemical products are on the right side.
6 0
3 years ago
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Each of the following reactions is incomplete. Match each of the following particles with the correct reaction in order to compl
kiruha [24]

Answer:

1. Option A. Beta decay minus 0 -1e

2. Option B. Alpha 4 2He

3. Option A. Beta decay minus 0 -1e

Explanation:

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2. 238 92U is undergoing alpha decay since the daughter nuclei produced has a decrease of 4 in the mass number and a decrease of 2 in the atomic number ie 234 90Th

3. 14 6C is undergoing beta decay minus since the daughter nuclei produced has the same mass number and the atomic number increased by 1 i.e 14 7N

Please see the attached photo for more details

4 0
3 years ago
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