The component of weight(
mg) that is responsible for the motion of boxes on ramp is:
Where m = mass of the boxes.
g = Acceleration due to gravity = 9.8
= The angle the ramp makes with the ground. In this case it is 30°.
Since the frictional force is:
μ*N.
Where,
μ = Frictional Coefficient
N = Normal to the ramp =
Therefore, the frictional force becomes =
= μ*
Apply Newton's second law we would get:
- μ*
=
=>
=
μ
-- (A)
Now according to equation of motion:
Where x = 5.8m
= 0
= 0
= 10.24
Plug in the value in the above equation you would get:
= 1.1328
Plug in
in equation (A) and solve for
μ, you would get,
μ = 0.4439
Answer: 1. As pen nib is split at the tip to provide the narrow capillary and the ink is drawn upto the point continuously.
2. In oil lamps, the oil is drawn up through the capillary of the wick.
3. Clay soils are damped as the water rises quickly to the surface through the capillaries.
4. Water and minerals rise in the plants through the fine capillaries.
5. Blotting paper absorbs ink through the pores.
Explanation:
the international system of unit of the aside from the branch system International is a unit is is the metric system used in Sin industries and medicine
Answer:
-2.5 is the answer to your question
Answer:
The box slides 0.58 m before stopping .
Explanation:
Given :
Spring constant , k = 100 N/m .
Compression in the spring , x = 20 cm .
Mass of box , m = 2.3 kg .
Coefficient of kinetic friction of the box on the surface is , .
Therefore , conserving energy of the system :
Putting value in above equation we get :
Therefore , the box slides 0.58 m before stopping .