Answer:
52 N
Explanation:
Given:
Work done= 1820 J, distance= 35 meters Force = ?
Formula for work done
W = F • d
Find F.
F = W / d
Substitute the given into the equation.
F = 1820 J / 35 m
= 52 N
Answer:
H = 109.14 cm
Explanation:
given,
Assume ,
Total energy be equal to 1 unit
Balance of energy after first collision = 0.78 x 1 unit
= 0.78 unit
Balance after second collision = 0.78 ^2 unit
= 0.6084 unit
Balance after third collision = 0.78 ^3 unit
= 0.475 unit
height achieved by the third collision will be equal to energy remained
H be the height achieved after 3 collision
0.475 ( m g h) = m g H
H = 0.475 x h
H = 0.475 x 2.3 m
H = 1.0914 m
H = 109.14 cm
-- Bob covered a distance of (32m + 45m) = 77 meters.
-- His displacement is the straight-line distance and direction
from his starting point to his ending point.
The straight-line distance is
D = √(32² + 45²)
D = √(1,024 + 2,025)
D = √3,049 = 55.22 meters
The direction is the angle whose tangent is (32/45) south of east.
tan⁻¹(32/45) = tan⁻¹(0.7111...) = 35.42° south of east.
Answer:
16.6 ms or 0.0166 s
Explanation:
If Q is the final charge, Q' is the initial charge, C the capacitance ,R is the resistance , t the time taken and τ the time constant,
[tex]Q = Q'( 1- e^{-t\div \tau })
τ = R C = (1.20×10³) (20×10⁻⁶) = 0.024 s
15 = 30 ( 1- e^{-t\div \ 0.024 })
( 1- e^{-t\div \ 0.024 }) = 15 ÷ 30
⇒ - e^{-t\div \ 0.024 }) = 0.5 -1
⇒ e^{-t\div \ 0.024 }) = 0.5
Taking logarithm to the base e on both sides of this equation,
⇒ t = 0.0166 seconds = 16.6 milli seconds