All categories

3 years ago

Please help don't for get to show work

1 answer:

3 0

-- Bob covered a distance of (32m + 45m) = 77 meters.

-- His displacement is the straight-line distance and direction
from his starting point to his ending point.

The straight-line distance is

D = √(32² + 45²)
D = √(1,024 + 2,025)
D = √3,049 = 55.22 meters

The direction is the angle whose tangent is (32/45) south of east.

tan⁻¹(32/45) = tan⁻¹(0.7111...) = 35.42° south of east.

You might be interested in

A submarine periscope uses two totally reflecting 45-45-90 prisms with total internal reflection on the sides adjacent to the 45

Likurg_2 [28]

Answer

Given,

Periscope uses 45-45-90 prisms with total internal reflection adjacent to 45°.

refractive index of water, n_a = 1.33

refractive index of glass, n_g = 1.52

When the light enters the water, water will act as a lens and when we see the object from the periscope the object shown is farther than the usual distance.

7 0

3 years ago

A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerat

Readme [11.4K]

Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

$s=ut-\dfrac{1}{2}at^2$

Put the value into the formula

$1200=92t+\dfrac{1}{2}\times4t^2$

$2t^2+92-1200=0$

$t=10\ sec$

We need to calculate the velocity

Using equation of motion

$v=u+at$

Put the value into the formula

$v=92+4\times10$

$v=132\ m/s$

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

$h'=h+ut-\dfrac{1}{2}at^2$

Put the value into the formula

$0=1200+132t-\dfrac{1}{2}\times9.8t^2$

$4.9t^2-132t-1200=0$

$t=34\ sec$

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

$t'=34+10$

$t'=44\ sec$

Hence, The rocket above the ground is in 44 sec.

7 0

4 years ago

At the base of a frictionless icy hill that rises at 25.0∘ above the horizontal, a toboggan has a speed of 12.9 m/s toward the h

Lemur [1.5K]

Explanation:

Below is an attachment containing the solution

4 0

3 years ago

On a smooth horizontal floor, an object slides into a spring which is attached to another mass that is initially stationary. Whe

saul85 [17]

Answer: (E) Momentum and mechanical energy

Explanation:

The momentum and the mechanical energy is basically conserved during the given interaction process as the forces on the given system are in the form of internal nature and then the momentum are get conserved.

According to the given question, on the smooth floor when an object are slides by using the spring then the momentum and the mechanical energy are conserved.

The mechanical energy is the combination of both the kinetic and the potential energy that is used for doing some amount of work. Therefore, Option (E) is correct answer.

5 0

3 years ago

Mercury has two satellites. True False (I NEED THE ANSWER ASAP!

anastassius [24]

Answer:

False

Explanation:

Mercury has 0 natural satellites.

8 0

4 years ago