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3 years ago

In general, how do you find the average velocity of any object falling in a vacuum?

1 answer:

5 0

In general, how do you find the average velocity of any object falling in a vacuum? (Assume you know the final velocity.) Multiply the final velocity by final time. 3. Calculate : Distance, average velocity, and time are related by the equation, d = v • t A

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At a certain location, Earth has a magnetic field of 0.60 â 10â4 T, pointing 75Â° below the horizontal in a north-south plane. A

krek1111 [17]

Answer:

a) $= 9.30\times 10^{-3} N$

b) $= 2.49\times 10^{-3} N$

Explanation:

Given data;

magnetic field $= 0.60 \times 10^{-4} T$

current I = 11 A

length of wire L = 14.6 m

Angle $\theta = 75 A$

a) Magnetic force due to current

$F = BIL sin \theta$

$= 0.60 \times 10^{-4} \times 11 \times 14.6 sin 75^o$

$= 9.30\times 10^{-3} N$

B) magnitude of force due upward current direction

$F = BIL sin \theta$

$= 0.60 \times 10^{-4} \times 11 \times 14.6 sin (75^o + 90^o)$

$= 2.49\times 10^{-3} N$

4 0

3 years ago

A car drives for 50 seconds and travels 2 meters what is its velocity

kupik [55]

Answer:

speed = distance/time so v = 100/50 m/sec = 2 m/sec.

D = 2T ⇐formula for distance, in meters, for trip duration in T seconds, ASSUMING CONSTANT SPEED.

8 0

3 years ago

Read 2 more answers

An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary

rusak2 [61]

Answer:

a) 5200 N b) 8800 N

Explanation:

a) tension in the cable when it was being lowered to the sea floor = weight of the object which acts downward ( equals the tension in the cable when the craft was stationary in opposite direction) - the drag force which will act upward = 7000 - 1800 = 5200 N

b) tension in the cable when the craft was being raised since the tension will act upward and the drag force and the weight will act downward = 7000 + 1800 = 8800 N

6 0

3 years ago

Two 10-cm-diameter charged rings face each other, 25.0cm apart. Both rings are charged to +20.0nC. What is the electric field st

Black_prince [1.1K]

Answer:

Part A:

$E_{midpoint}=0$

Part B:

$E_{center}=2711.7558 N/C$

Explanation:

Part A:

Formula of Electric Field Strength:

$E=\frac{1}{4\pi\epsilon}\frac{xQ}{(x^2+R^2)^{3/2}}$

Where:

x is the distance from the ring

R is the radius of the ring

$\epsilon$ is constant permittivity of free space=8.854*10^-12 farads/meter

Q is the charge

For right Ring E at the midpoint can be calculated as:

x for right plate=25/2=12.5 cm=0.125 m

Radius=R=10/2=5 cm=0.05 m

$E_{right}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0.125)*(20*10^{-19})}{((0.125)^2+(0.05)^2)^{3/2}}\\E_{right}=9208.1758 N/C$

For Left Ring E at the midpoint can be calculated as:

Since charge on both plates is +ve and same in magnitude, the electric field will be same for both plates.

$E_{left}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0.125)*(20*10^{-19})}{((0.125)^2+(0.05)^2)^{3/2}}\\E_{left}=9208.1758 N/C$

Electric Field at midpoint:

Both rings have same magnitude but the direction of fields will be opposite as they have same charge on them.

$E_{midpoint}=E_{left}-E_{right}\\E_{midpoint}=9208.1758-9208.1758\\E_{midpoint}=0$

Part B:

At center of left ring:

Due to left ring Electric field at center is zero because x=0.

$E_{left}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0)*(20*10^{-19})}{((0)^2+(0.05)^2)^{3/2}}\\E_{left}=0 N/C$

Due to right ring Electric field at center of left ring:

Now: x=25 cm= o.25 m (To the center of left ring)

$E_{right}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0.25)*(20*10^{-19})}{((0.25)^2+(0.05)^2)^{3/2}}\\E_{right}=2711.7558 N/C$

Electric Field Strength at center of left ring is same as that of right ring.

$E_{center}=2711.7558 N/C$

5 0

3 years ago

If its wavelength were doubled, its energy would be If its wavelength were doubled, its energy would be 4E. 2E. 12E. 14E.

ANEK [815]

The wavelength was doubled, and its energy will be increased by 4 times.

looking at the formula

energy $E = MC^2$

also, $c = \lambda \times \nu$

hence it is clear from above that energy is directly proportional to the square of the wavelength.

hence, The wavelength was doubled, and its energy will be increased by 4 times.

<h3>What is Wavelength?</h3>

The distance over which a periodic wave's shape repeats is known as the wavelength in physics.
It is a property of both traveling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.
The spatial frequency is the reciprocal of the wavelength. The Greek letter lambda is frequently used to represent wavelength.
The term wavelength is occasionally used to describe modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.

To learn more about wavelength with the given link

brainly.com/question/13533093

#SPJ4

5 0

2 years ago