Answer:
Explanation:
The nuclear model of the atom was suggested by Ernest Rutherford based on his experiment on a thin gold foil.
To explain his observations, he suggested the atomic or nuclear model.
In this model, the atom has a small positively charged center called the nucleus.
All the mass of the atom is concentrated here in the nucleus.
Surrounding the nucleus is a large space
It is the extranuclear part
This part contains electrons.
A nucleus surrounded by electrons forms the nuclear model of the atom.
Answer:
<em>C</em> H2SO4 = 9.79 M
Explanation:
- molarity (M) ≡ # dissolved species / V sln
- H2SO4 ↔ H3O+ + SO4-
∴ %w/w H2SO4 = 960% = g H2SO4 / g sln * 100
⇒ 9.6 = g H2SO4 / g sln
calculation base: 1000 g sln
⇒ g H2SO4 = 9600g
⇒<em> </em>mol<em> </em>H2SO4 =<em> </em>9600 g H2SO4 * ( mol H2SO4/ 980g H2SO4 ) = 9.796 mol H2SO4
⇒ V sln = 1000g sln / 1000g/L = 1 L sln
∴ ρ H20 ≅ 1000 Kg/m³ = 1000 g/L
⇒ <em>C</em> H2SO4 = 9.796 mol H2SO4 / 1 L sln
⇒ <em>C</em> H2SO4 = 9.796 M
Answer:
No, you cannot.
Explanation:
Due to the Law of Conservation of Energy all chemical equations have to be balcned. The Law of Conservation of energy states that matter cannot be neither created nor destroyed. By having more atoms on either side, you are breaking this law.
Answer:
All strong acids have a higher value of and the equilibrium for the reaction with water lies far to the right.
Explanation:
All strong acids dissociate completely in the solution. Higher the value of dissociation constant of the acid, higher will be the dissociation of the acid.
The reaction of the acid with water will be favored in the forward direction for acids having higher dissociation constant value ().
The dissociation of a strong acid say HA in water is shown below
Higher the value of , more will be the dissociation of the acid in water. The reaction will move far to the right side.
Answer:
T₁ = 563.19 K
Explanation:
Given data:
Initial volume = 359 mL
Final volume = 269 mL
Final temperature = 422 K
Initial temperature = ?
Solution:
The given problem will be solve through the Charles Law.
Charles Law:
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₁ = V₁T₂ / V₂
T₁ = 359 mL × 422 K / 269 mL
T₁ = 151498 mL.K / 269 mL
T₁ = 563.19 K