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frutty [35]
3 years ago
8

How are thunderstorms kept alive?

Physics
1 answer:
Burka [1]3 years ago
5 0

Answer:

E step leader

Explanation:

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A raindrop of radius r falls from a certain height h above the ground. The work done by
lisabon 2012 [21]

Answer:

fhc

Explanation:

chchfufuufufyfydyedhxhfud wyruficjc

5 0
3 years ago
our lab partner wears a new pair of sneakers to lab and, rather than performing the required experiments, you decide to measure
Dafna1 [17]

Answer:

The coefficient of static friction between your partner and the floor is 0.55

Explanation:

Given:

Mass m = 59 Kg

Frictional force F_{s}  = 318.3 N

From the formula of frictional force,

 F_{s} = \mu_{s} mg

Where \mu _{s} = coefficient of static friction, g = 9.8 \frac{m}{s^{2} }

Put the above values and find the coefficient of static friction.

318.3 = \mu_{s} \times 59 \times 9.8

\mu_{s} = 0.55

Therefore, the coefficient of static friction between your partner and the floor is 0.55

4 0
3 years ago
The oxygen in earth’s atmosphere is a product of what?
Nina [5.8K]

Answer:

The answer is tiny organisms known as cyanobacteria, or blue-green algae. These microbes conduct photosynthesis: using sunshine, water and carbon dioxide to produce carbohydrates and, yes, oxygen.

7 0
3 years ago
A 50 g sample of an unknown metal is heated to 90.0C. It is placed in a perfectly insulated container along with 100 g of water
Scrat [10]

Answer:

0.64 J/g°C

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat

m = mass (g)

c = specific heat capacity

∆T = change in temperature (°C)

In this case:

Q (water) = - Q (metal)

mc∆T (water) = - mc∆T (metal)

According to the information in this question,

For water; m = 100g, c = 4.18J/g°C, ∆T = (25°C - 20°C)

For metal; m = 50g, c =?, ∆T = (25°C - 90°C)

mc∆T (water) = - mc∆T (metal)

100 × 4.18 × (25°C - 20°C) = - {50 × c × (25°C - 90°C)}

100 × 4.18 × 5 = - {50 × c × -65}

2090 = -{-3250c}

2090 = 3250c

c = 2090/3250

c = 0.643

c = 0.64J/g°C

7 0
3 years ago
Read 2 more answers
If a force of 12 N is applied to an object with a mass of 2 kg, what will be its acceleration?
nadezda [96]
F = ma,  Where F is force is in N, mass is in kg, = 2kg, a is acceleration in m/s²

12 = 2a

2a = 12

a = 12/2

a = 6

Acceleration = 6 m/s²
7 0
3 years ago
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