Molar mass of CO2 = 44.01 g/mol
Answer:
Explanation:
As per Boltzman equation, <em>kinetic energy (KE)</em> is in direct relation to the <em>temperature</em>, measured in absolute scale Kelvin.
Then, <em>the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be </em><em>3 times</em><em> such temperature.</em>
So, you must just convert the given temperature, 32°F, to kelvin scale.
You can do that in two stages.
- First, convert 32°F to °C. Since, 32°F is the freezing temperature of water, you may remember that is 0°C. You can also use the conversion formula: T (°C) = [T (°F) - 32] / 1.80
- Second, convert 0°C to kelvin:
T (K) = T(°C) + 273.15 K= 273.15 K
Then, <u>3 times</u> gives you: 3 × 273.15 K = 819.45 K
Since, 32°F has two significant figures, you must report your answer with the same number of significan figures. That is 820 K.
Answer:
A radio telescope is simply a telescope that is designed to receive radio waves from space.
radio telescopes helps to study naturally occurring radio light from stars, galaxies, black holes, and other astronomical objects. We can also use them to transmit and reflect radio light off of planetary bodies in our solar system.
<span>Answer:
2 C8H18 + 25 O2 => 16 CO2 + 18 H2O
1.0 kg = 1000 g C8H18 = 1000 g / 114.2293 g/mole = 8.75 moles C8H18
8.75 moles C8H18 produce (16/2) (8.75) = 70 moles CO2
70 moles CO2 = (70 moles) (44.0096 g/mole) = 3081 g CO2 = 3.1 kg CO2</span>
1) baking soda (NaHCO₃ - sodium bicarbonate) is white, solid, crystalline salt or <span>appears as a fine powder.
2) vinegar is mixture of acetic acid (CH</span>₃COOH) and water (H₂O). Vinerar is colourless liquid with <span>sour taste and pungent smell.
3) Chemical reaction: </span>NaHCO₃ + CH₃COOH → CH₃COONa + CO₂ + H₂O.
Jane should see bubbles of carbon(IV) dioxide.
4) sodim acetate (CH₃COONa) is solid and carbon dioxide (CO₂) is gas.
5) Jane can put burning match over reaction, the fire on the match is going to put out because of carbon dioxide.