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ipn [44]
2 years ago
13

¿cual es el volumen de solución que contiene 10 gramos de NaCl en 100 mL de solución?.

Chemistry
1 answer:
Ivenika [448]2 years ago
8 0

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Which elements have the most similar chemical properties?
bixtya [17]

Answer:

a. Be and Mg

Explanation:

Be (beryllium) and Mg (magnesium) are both found in the alkaline earth metals family (group 2) on the periodic table. Elements in the same family or group have similar properties,

Ca and Br are in groups 2 and 17

Cl and Ar are in groups 17 and 18

Na and P are in groups 1 and 15

4 0
3 years ago
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The best determinant of how an individual measures their quality of life is _______.
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C is the correct answer
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3 years ago
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Someone help me with chemistry on my account/page please :))
Gemiola [76]

Answer:

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Explanation:

5 0
2 years ago
How do you do this? very confused
Vlad [161]
The problem you have written you almost have it solved.  Take the moles that you have calculated and multiply that by the molecular weight to get the grams.

The STP problem:
use the moles you calculated along with 1 atm for Pressure, and 273 for the temperature and plug into the PV = nRT equation.  (also use 0.0821 for R)

From there you can solve for the volume

Hope this helps!
4 0
3 years ago
Can you please help me and can you show your work please
natali 33 [55]

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

1.2mol*\frac{40.00g}{1mol} =41.2g

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

45g*\frac{1mol}{180.15g}=0.25g

4. Here, since the molar mass of ammonia is 17.03 g/mol:

20mol*\frac{17.03g}{1mol}=340.6g

5. Here, since the molar mass of SO2 is 64.06 g/mol:

48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules

Best regards!

5 0
3 years ago
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