The velocity of the earth in its orbit around the sun is
Explanation
Given that the distance between sun and earth is 149500,000,000m
.
This is the radius of the nearly circular orbit of the earth around the sun.
r=149,500,000,000m=
Answer:
Please refer to the figure.
q1 is a negative charge, and q2 and q3 are positive charges. So, the force exerted by q1 on q3 is attractive, and the force exerted by q2 on q3 is repulsive, which means F13 is directed towards left, and F23 is also directed towards left.
The net force on q3 is the sum of these two forces:
Since both forces are directed towards left, their sign should be negative.
I would think between, 36.5N or 40.5N