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3 years ago

What is conductivity?

Physics

1 answer:

kirill [66]3 years ago

3 0

Answer:

Conductivity is the measure of the ease at which an electric charge or heat can pass through a material. A conductor is a material that gives very little resistance to the flow of an electric current or thermal energy.

Explanation:

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A train moves at a constant velocity of 90 km/h. How far will it move in 0.25h?<br>

Serjik [45]

In 0.25h it will move in 22.5 kilometers.

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2 years ago

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Mayan kings and many school sports teams are named for the puma, cougar, or mountain lion felis concolor, the best jumper among

denis23 [38]

To reach a vertical height of 13.8 ft against gravity, which has an acceleration of 32 ft/s^2, the required vertical speed can be calculated from the equation:
vi^2 - vf^2 = 2*g*h
Given that it has vf = 0 (it is not moving vertically at its maximum height), g = 32, and h = 13.8, we can solve for vi:
vi^2 = 29.72 ft/s
This is only its vertical speed, so this is equivalent to its original speed multiplied by the sine of the angle:
29.72 ft/s = (v_original)*(sin 42.2<span>°</span>)
v_original = 44.24 ft/s
Converting to m/s, this can be divided by 3.28 to get 13.49 m/s.

4 0

3 years ago

g John is walking along a trail when he comes to the bottom of a steep cliff. Before trying to climb up it, he wonders how high

s344n2d4d5 [400]

Answer:

179.655m

Explanation:

Given

Maximum speed of the arrow v = 60m/s

Time taken to hit the top of the cliff t = 7.0s

Required

Height of the cliff H

Using the equation of motion

H = vt + 1/2gt²

Substitute into the formula:

H = 60(7) + 1/2 (-9.81)(7²) (g is negative due to upward motion of the arrow)

H = 420-4.905(49)

H = 420-240.345

H = 179.655m

Hence the cliff is 179.655m high

4 0

2 years ago

A tennis ball of mass 44.0 g is held just above a basketball of mass 594 g. With their centers vertically aligned, both are rele

ZanzabumX [31]

Answer:

u = 4.6 m/s

h = 8.01 m

Explanation:

Given:

Mass of the tennis ball, m = 44.0 g

Mass of the basket ball, M = 594 g

Height of fall, h = 1.08m

Now,

we have

$u^2-u'^2 = 2as$

where, s = distance = h

a = acceleration

u = final speed before the collision

u' = initial speed

since it is free fall case

thus,

a = g = acceleration due to gravity

u' = 0

thus we have

$u^2-0^2 = 2\times9.8\tiimes1.08$

$u = \sqrt{21.168}$

u = 4.6 m/s

b) Now after the bounce, the ball moves with the same velocity

thus, v = v₂

thus,

final speed ( $v_f$ ) = v = 4.6 m/s

Then conservation of energy says

$\frac{1}{2}mu_1^2+\frac{1}{2}Mu_2^2 = \frac{1}{2}mv_1^2+\frac{1}{2}Mv_2^2$

also

applying the concept of conservation of momentum

we have

mu₁ + Mu₂ = mv₁ + Mv₂

u₁ =velocity of the tennis ball before collision = -4.6 m/s

u₂ = velocity of the basketball before collision= 4.6 m/s

v₁ = velocity of the tennis ball after collision

v₂ = velocity of the basketball after collision

substituting the values in the equation, we get

Now,

solving both the equations simultaneously we get

$v = (\frac{2M}{m+M})u_1+(\frac{m-M}{m+M})u_2$

substituting the values in the above equation we get

$v = (\frac{2\times594}{44+594})(-4.6)+(\frac{44-594}{44+594})4.6$

$v = -8.565-3.965$

$v = -12.53m/s$

here negative sign depicts the motion of the ball in the upward direction

now the kinetic energy of the tennis ball

$K.E = \frac{1}{2}mv^2$

$K.E = \frac{1}{2}44\times 10^{-3}kg\times 12.53^2$

K.E = 3.45 J

also at the height the K.E will be the potential energy of the tennis ball

thus,

3.45 J = mgh

3.45 = 44 × 10⁻³ × 9.8 × h

h = 8.01 m

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3 years ago

When you hold your hands at your sides, you may have noticed that the veins sometimes bulge--the height difference between your

hodyreva [135]

To solve this problem it is necessary to use the concepts related to pressure and pressure, absolute and atmospheric.

Average arterial pressure in the hands,

$P = 100mmHg+ h*\rho_{blood}g$

Where,

P = Pressure

h = height (at this case the length of the arm)

Replacing with our values

$P = 100mm(Hg)+(600mm)(\frac{\rho_{blood}}{\rho_{mercury}})(Hg)$

$P = 100mmHg+600*\frac{1060}{13600}mmHg$

$P = 100mmHg+46.765mmHg$

$P = 146.765mmHg$

Where,

$\rho_{blood} = 1060Kg/m^3$

$\rho_{mercury}=13600Kg/m^3$

Therefore the pressure is 146.765mmHg

7 0

3 years ago

What is conductivity?​

What is conductivity?