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3 years ago

What action will slow down the rate of a reaction?

Physics

1 answer:

andreyandreev [35.5K]3 years ago

5 0

B. Decreasing surface area of a solid reactant. The more surface area showing, the quicker the reaction rate.

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During the first 5 seconds after a ball is dropped from rest, how far will it fall?

agasfer [191]

The answer is 125metre

5 0

3 years ago

An electric device, which heats water by immersing a resistance wire in the water, generates 50 cal of heat per second when an e

Oksi-84 [34.3K]

Answer:

0.69 ohm

Explanation:

Heat generated per second, H = 50 cal/s

Potential difference, V = 12 V

Let R is the resistance of coil.

The formula for the heat is given by

$H = \frac{V^{2}}{R}t$

$50\times 4.186 = \frac{12^{2}}{R}\times 1$

R = 0.69 ohm

3 0

3 years ago

A vector has components Ax = 52.0 m and Ay = 41.0 m. Find: (a) The length of the vector A.

vredina [299]

Answer:

Part a)

A = 66.2 m

Part b)

Angle = 38.35 degree

Explanation:

Part a)

Length of the vector is the magnitude of the vector

here we know that

$A_x = 52.0 m$

$A_y = 41.0 m$

now we have

$A = \sqrt{A_x^2 + A_y^2}$

$A = \sqrt{52^2 + 41^2}$

$A = 66.2 m$

Part b)

Angle made by the vector is given as

$tan\theta = \frac{A_y}{A_x}$

$tan\theta = \frac{41}{52}$

$\theta = 38.25 degree$

4 0

4 years ago

A person throws a 10kg rock straight up. If the person exerted 3500N of force on the rock over a distance

pickupchik [31]

Answer:

h = 17.83[m]

Explanation:

By means of the working equation which is equal to the product of force by distance, we can find the energy printed at the launch.

$W=F*d$

where:

W = work [J]

F = force = 3500 [N]

d = distance = 0.5 [m]

Now replacing:

$W= 3500*0.5\\W=1750[J]$

Now, this same work is converted to kinetic energy, necessary for the body to move with an initial velocity. And by energy conservation, we can say that kinetic energy is transformed into potential energy. That is, the kinetic energy will be equal to the potential energy.

$W=E_{kin}=E_{pot}$

where:

Ekin = kinetic energy [J]

Epot = potential energy [J]

Therefore:

$1750 = m*g*h\\1750=10*9.81*h\\h = 17.83[m]$

4 0

3 years ago

Calculate the power of a train that uses 2MJ of chemical energy in 4<br> seconds.

nadya68 [22]

Answer:

500 kW

Explanation:

Given that,

Energy of the train, E = 2 MJ = 2×10⁶ J

Time, t = 4 seconds

We need to find the power of the train. We know that,

Power = energy/time

So,

$P=\dfrac{2\times 10^6}{4}\\\\P=500000\ W\\\\or\\\\P=500\ kW$

So, the power of the train is equal to 500 kW.

6 0

3 years ago