Answer:
T = 480.2N
Explanation:
In order to find the required force, you take into account that the sum of forces must be equal to zero if the object has a constant speed.
The forces on the boxes are:
(1)
T: tension of the rope
M: mass of the boxes 0= 49kg
g: gravitational acceleration = 9.8m/s^2
The pulley is frictionless, then, you can assume that the tension of the rope T, is equal to the force that the woman makes.
By using the equation (1) you obtain:
![T=Mg=(49kg)(9.8m/s^2)=480.2N](https://tex.z-dn.net/?f=T%3DMg%3D%2849kg%29%289.8m%2Fs%5E2%29%3D480.2N)
The woman needs to pull the rope at 480.2N
Answer:
a
![z= 2.5 \ m](https://tex.z-dn.net/?f=z%3D%202.5%20%5C%20m)
b
![z = (1 \ m , 4 \ m )](https://tex.z-dn.net/?f=z%20%3D%20%20%281%20%5C%20m%20%2C%20%204%20%5C%20m%20%29)
Explanation:
From the question we are told that
Their distance apart is ![d = 5.00 \ m](https://tex.z-dn.net/?f=d%20%3D%20%205.00%20%5C%20m)
The wavelength of each source wave ![\lambda = 6.0 \ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%206.0%20%5C%20m)
Let the distance from source A where the construct interference occurred be z
Generally the path difference for constructive interference is
![z - (d-z) = m \lambda](https://tex.z-dn.net/?f=z%20-%20%28d-z%29%20%3D%20%20m%20%5Clambda)
Now given that we are considering just the straight line (i.e points along the line connecting the two sources ) then the order of the maxima m = 0
so
![z - (5-z) = 0](https://tex.z-dn.net/?f=z%20-%20%285-z%29%20%3D%20%200)
=> ![2 z - 5 = 0](https://tex.z-dn.net/?f=2%20z%20-%205%20%3D%20%200)
=> ![z= 2.5 \ m](https://tex.z-dn.net/?f=z%3D%202.5%20%5C%20m)
Generally the path difference for destructive interference is
![|z-(d-z)| = (2m + 1)\frac{\lambda}{2}](https://tex.z-dn.net/?f=%7Cz-%28d-z%29%7C%20%3D%20%282m%20%2B%201%29%5Cfrac%7B%5Clambda%7D%7B2%7D)
=> ![|2z - d |= (0 + 1)\frac{\lambda}{2}](https://tex.z-dn.net/?f=%7C2z%20-%20d%20%7C%3D%20%280%20%2B%201%29%5Cfrac%7B%5Clambda%7D%7B2%7D)
=> ![|2z - d| =\frac{\lambda}{2}](https://tex.z-dn.net/?f=%7C2z%20-%20d%7C%20%3D%5Cfrac%7B%5Clambda%7D%7B2%7D)
substituting values
![|2z - 5| =\frac{6}{2}](https://tex.z-dn.net/?f=%7C2z%20-%205%7C%20%3D%5Cfrac%7B6%7D%7B2%7D)
=> ![z = \frac{5 \pm 3}{2}](https://tex.z-dn.net/?f=z%20%20%3D%20%20%5Cfrac%7B5%20%5Cpm%203%7D%7B2%7D)
So
![z = \frac{5 + 3}{2}](https://tex.z-dn.net/?f=z%20%3D%20%20%5Cfrac%7B5%20%2B%203%7D%7B2%7D)
![z = 4\ m](https://tex.z-dn.net/?f=z%20%3D%20%204%5C%20m)
and
![z = \frac{ 5 -3 }{2}](https://tex.z-dn.net/?f=z%20%3D%20%20%5Cfrac%7B%205%20-3%20%7D%7B2%7D)
=> ![z = 1 \ m](https://tex.z-dn.net/?f=z%20%3D%20%201%20%5C%20m)
=> ![z = (1 \ m , 4 \ m )](https://tex.z-dn.net/?f=z%20%3D%20%20%281%20%5C%20m%20%2C%20%204%20%5C%20m%20%29)
Violet light is at the end of the visible light section of the electromagnetic spectrum. Ultraviolet rays are directly next to violet rays on the EM Spectrum.
Answer:
meiosis is a kind of cell division which occurs in special cells like gametes in which the daughter cells have half the numbers of chromosomes than the parent cells .
hence we can say that by this cell division 2 haploid cells are formed.
The first thing you should do for this case is to find the horizontal and vertical components of the forces acting on the body.
We have then:
Horizontal = 9-9.2cos (58) = 4.124742769 N.
Vertical = 9.2sin (58) = 7.802042485 N
Then, the resulting net force is:
F = √ ((4.124742769) ^ 2 + (7.802042485) ^ 2) = 8.825268826 N
Then by definition:
F = m * a
Clearing the acceleration:
a = F / m
a = (8.825268826) / (3.0) = 2.941756275 m / s ^ 2
answer:
The magnitude of the body's acceleration is
2.941756275 m / s ^ 2