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Brums [2.3K]
3 years ago
11

If a truck runs into a wall and stops, the truck loses momentum. Because

Physics
1 answer:
nignag [31]3 years ago
6 0
The momentum goes to the wall
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An object moving at 15 m/s slows uniformly at a rate of 2.0 m/s each second for 5.0 s. What is its final speed?​
NeX [460]
Hey there!

We are given ,

Acceleration, a = -2m/s^2

Initial velocity , u = 15m/s

Time , t = 5 seconds

We know that ,
V=u+at

Now , final speed ,

V = 15+(-2)(5)

V = 15-10

V = 5 m/s -> final speed

Hope this helps you dear :)
Have a good day <3

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2 years ago
Which best describes a chemical reaction? the rearrangement of atoms by breaking and reforming chemical bonds a reaction that ab
Ede4ka [16]

Answer:

A

Explanation:

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3 years ago
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The mass of an atom is
suter [353]

Answer:

Atomic mass is defined as the number of protons and neutrons in an atom, where each proton and neutron has a mass of approximately 1 amu (1.0073 and 1.0087, respectively). The electrons within an atom are so miniscule compared to protons and neutrons that their mass is negligible.

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What is the term used to label the energy levels of electrons?
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3 years ago
Diagram shows the velocity time graph for a particle moving in 16 seconds.
Leya [2.2K]

Answer:

The detailed calculations are shown below;

Explanation:

a)The maximum acceleration of the particle:

  It is seen that the maximum change in velocity is at the time between 8s to 10s.

              Maximum acceleration: \frac{V}{t}

                                                    = \frac{20}{2}

                                                    = 10 m/s^{2}

b) The deceleration of the particle

          The velocity of particle is decreased after 10s so,

                     deceleration = - \frac{40}{6}

                                           = - 6.67 m/s^{2}

c)The total distance traveled by the particle = Area under the curve

                               = \frac{1}{2}* 4*20 + 4*20 +  \frac{1}{2}* 2*20+ 2*20+ \frac{1}{2}* 40*16

                                                       = 290 m

d)The average velocity of the particle = \frac{Area under the curve}{Total time}

                                                               = \frac{290}{16}

                                                               = 18.12 m/s

3 0
3 years ago
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