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Kisachek [45]
4 years ago
12

During a demolition derby, vehicle 1 collided vehicle 2 going in the opposite direction and came to an immediate stop. If the ve

hicles are of different masses and were not travelling at the same velocity, what can be concluded about them? *
Physics
1 answer:
snow_tiger [21]4 years ago
7 0

Answer:

Their change in momentum is the same in magnitude and opposite in direction

Explanation:

The momentum of an object is defined as:

p=mv

where

m is the mass of the object

v is the velocity of the object

Therefore, the change in momentum of an object is

\Delta p = m\Delta v

where \Delta v is the change in velocity.

During a collision, the force experienced by an object is equal to the rate of change of momentum:

F=\frac{\Delta p}{\Delta t}

where \Delta t is the duration of the collision.

According to Newton's third law of motion, the force exerted by vehicle 1 on vehicle 2 during the collision is equal (and opposite) to the force exerted by vehicle 2 on vehicle 1, so

F_1=-F_2

Which means

\frac{\Delta p_1}{\Delta t}=-\frac{\Delta p_2}{\Delta t}

And since the duration of the collision is the same for the two vehicles, this becomes

\Delta p_1 =-\Delta p_2

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3 years ago
A student lifts a box of books 2 meters with a force of 45 N. He then carries the box 10 meters to the living room. What is the
Alisiya [41]

Answer:

90J

Explanation:

The only time work is being done is when he lifts the box off the ground. Therefore, using the work formula, 2 x 45, you get 90J. Hope this helps someone.

5 0
3 years ago
After your patched the roof, you dropped the hammer off the house and you heard it land on your toolbox on the ground 3.3s later
Schach [20]

Answer:

53.36 m.

Explanation:

Initial velocity of the toolbox u = 0

acceleration due to gravity g = 9.8 m s⁻²

time t = 3.3 s

height of roof h = ?

h = ut + 1/2 g t²

= 0 + .5 x 9.8 x 3.3²

= 53.36 m.

3 0
4 years ago
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distanc
dem82 [27]

Explanation:

It is known that the relation between speed and distance is as follows.

               velocity = \frac{distance}{time}

As it is given that velocity is 6 m/s and distance traveled by the bear is (d + 29). Therefore, time taken by the bear is calculated as follows.

         t_{bear} = \frac{(d + 29)}{6 m/s} ............. (1)

As the tourist is running in a car at a velocity of 4.2 m/s. Hence, time taken by the tourist is as follows.

              t_{tourist} = \frac{d}{4.2} ............. (2)

Now, equation both equations (1) and (2) equal to each other we will calculate the value of d as follows.

              t_{bear} = t_{tourist}

       \frac{(d + 29)}{6 m/s} = \frac{d}{4.2}

                   4.2d + 121.8 = 6d

                         d = \frac{121.8}{1.8}

                            = 67.66

Thus, we can conclude that the maximum possible value for d is 67.66.

5 0
3 years ago
What acceleration would a 18 kg box have if we pushed it with a force of 250 N across a surface that
konstantin123 [22]

Answer:

a=0.08\ m/s^2

Explanation:

Given that,

Mass of a box, m = 18 kg

It is pushed with a force of 250 N

The coefficient of friction is 0.8

We need to find the acceleration of the box.

Normal force acting on the box,

N = mg

M = 18 × 10

N = 180 N

The force acting on the force in terms of coefficient of friction is given by :

F=\mu mg\\\\\text{or}\\\\ ma=\mu mg\\\\a=\dfrac{\mu }{g}\\\\a=\dfrac{0.8}{10}\\\\a=0.08\ m/s^2

So, the acceleration of the box is 0.08\ m/s^2

3 0
4 years ago
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