"60 kg" is not a weight. It's a mass, and it's always the same
no matter where the object goes.
The weight of the object is
(mass) x (gravity in the place where the object is) .
On the surface of the Earth,
Weight = (60 kg) x (9.8 m/s²)
= 588 Newtons.
Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to 5R from the center, the gravity out there is
(1R/5R)² = (1/5)² = 1/25 = 0.04 of its value on the surface.
The object's weight would also be 0.04 of its weight on the surface.
(0.04) x (588 Newtons) = 23.52 Newtons.
Again, the object's mass is still 60 kg out there.
___________________________________________
If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink.
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.
Answer:
small amounts of mass are converted to large amounts of energy
Explanation:
According to the mass-energy equivalence, which Albert Einstein initially proposed as a general principle. It was revealed that mass and energy are connected and that a "small amount of mass can be converted into enormous amounts of energy."
Using the formula E=mc^2. This means Energy equals mass times the speed of light squared.
Hence, it is true that "small amounts of mass are converted to large amounts of energy."
Answer:
B
Explanation:
The normal force would be that the ramp would be dry
Answer:843.75kg
Explanation:
kinetic energy(ke)=432000j
Velocity(v)=32m/s
Mass(m)=?
Ke=(mxv^2)/2
432000=(mx32^2)/2
432000=(mx32x32)/2
Cross multiplying we get
432000x2=(mx1024)
864000=1024m
Divide both sides by 1024
864000/1024=1024m/1024
843.75=m
m=843.75kg