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White raven [17]
3 years ago
11

If the coefficient of static friction at d is μd = 0.3, determine the smallest vertical force that can be applied tangentially t

o the wheel which will cause motion to impend.
Physics
1 answer:
const2013 [10]3 years ago
5 0

Answer:

The minimum force is required is, f = 0.3 mg  Newton

Explanation:

Given data,

The coefficient of the static friction, μₓ = 0.3

Let the mass of the wheel is, m = M kg

The minimum force required to set the wheel in motion is equal to the force of static friction. This amount of force can be applied tangentially to the wheel in a vertical direction to set the wheel in motion.

                              <em> Fₓ = μₓ. F</em>

Where F is the normal force acting on the wheel and it is equal to mg.

Therefore, the minimum force is required is, f = 0.3 mg  Newton

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1 year ago
Cheetahs can accelerate to a speed of 19.6 m/s in 2.45 s and can continue to accelerate to reach a top speed of 27.6 m/s . Assum
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v_{top} = 27.7 \frac{m}{s} * \frac{1 \ mi}{ 1609.34 \ m}

v_{top} = 27.7 \frac{m}{s} * \frac{1 \ mi}{ 1609.34 \ m}

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<h3>hours from seconds</h3>

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as the seconds are dividing in the velocity, we know divide by 1 hour.

\frac{1 \ h}{ 1 \ h} = \frac{3600 \ s}{ 1 \ h}

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and know we just multiply our top speed by this conversion factor

v_{top} = 0.0172120 \frac{mi}{s}  \frac{3600 \ s}{ 1 \ h}

v_{top} = 61.96 \frac{mi}{h}

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