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liq [111]
3 years ago
5

Define one standard meter, one standard kilogram and one second

Physics
1 answer:
lidiya [134]3 years ago
6 0
<h3>The metre is the length of the path travelled by light in vacuum during a time interval of 1299 792 458 of a second.</h3>

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Escribo dentro del paréntesis la letra (F) si el enunciado es falso o (V) si el enunciado es verdadero. Fundamento si mi elecció
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Answer:

El primero es (V) y el segundo es(f)

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What is true of all particles of gas enclosed within a container?
Andre45 [30]
Theyre all in constant motion

6 0
3 years ago
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An astronaut has a mass of 75 kg and is floating in space 500 m from his 125,000 kg spacecraft. What will be the force of gravit
nikdorinn [45]

Answer:

1. 2.5×10¯⁹ N

2. 3.33×10¯¹¹ m/s²

Explanation:

1. Determination of the force of attraction.

Mass of astronaut (M₁) = 75 Kg

Mass of spacecraft (M₂) = 125000 Kg

Distance apart (r) = 500 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

The force of attraction between the astronaut and his spacecraft can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 75 × 125000 / 500²

F = 2.5×10¯⁹ N

Thus, the force of attraction between the astronaut and his spacecraft is 2.5×10¯⁹ N

2. Determination of the acceleration of the astronaut.

Mass of astronaut (m) = 75 Kg

Force (F) = 2.5×10¯⁹ N

Acceleration (a) of astronaut =?

The acceleration of the astronaut can be obtained as follow:

F = ma

2.5×10¯⁹ N = 75 × a

Divide both side by 75

a = 2.5×10¯⁹ / 75

a = 3.33×10¯¹¹ m/s²

Thus, the acceleration the astronaut is 3.33×10¯¹¹ m/s²

5 0
2 years ago
What scientific observation did Edwin Hubble use to determine distances between galaxies?
Cerrena [4.2K]

Answer: the expanding universe

Explanation:

Hope that helps!

7 0
3 years ago
All celestial objects we tracted to each other by gravity.Asteroids A and B are 5 meters (m) part. Asteroids C and D are also 5
Nadusha1986 [10]
A. Between asteroids C and D because gravitational attraction is greatest with increased mass.
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