The impulse is (force) x (time) = (20 N) x (20 sec) = 400 N-sec
When we grind through the units, we find that the [newton-second]
is exactly the same as the [kilogram-meter/sec] unit-wise, and once
we know that, it doesn't surprise us to learn that impulse is equivalent
to a change in momentum (mass x speed ... also kg-m/s).
So this impulse exerted on the moving object adds 400 kg-m/s of
linear momentum to its motion, directed to the right. That may or
may not be the total change in its momentum during that 20-sec,
because our 20-N may not be the only force acting on it.
Answer:
Part a) When collision is perfectly inelastic
Part b) When collision is perfectly elastic
Explanation:
Part a)
As we know that collision is perfectly inelastic
so here we will have
so we have
now we know that in order to complete the circle we will have
now we have
Part b)
Now we know that collision is perfectly elastic
so we will have
now we have
As the resistance increase the current decreases and vice versa
Answer:
Rest and motion are the relative terms because they depend on the observer's frame of reference. So if two different observers are not at rest with respect to each other, then they too get different results when they observe the motion or rest of a body.
The direction of the acceleration is the same as the direction of the net force: 34 degrees. Apply the equation <eq04017> to find the magnitude of the net force, giving you 35.4 N. Use the magnitude of the force and the mass to find the magnitude of the acceleration: a = F/m = (35.4 N)/(0.10 kg) = 354 m/s2.
