Answer:
New volume (V2) = 60 liter
Explanation:
Given:
Amount of helium (V1) = 20 Liter
Temperature (T1) = 100°K
Temperature (T2) = 300°K
Find:
New volume (V2)
Computation:
According to Gas Law:
V1 / T1 = V2 / T2
20 / 100°K = V2 / 300°K
V2 = 60 liter
New volume (V2) = 60 liter
Answer:
18.73 m/s^2
Explanation:
f = 2662 rpm = 2662 / 60 rps
r = 6.725 cm = 0.06725 m
Acceleration, a = r w
a = r x 2 x pi x F
a = 0.06725 × 2 × 3.14 × 2662 / 60
a = 18.73 m/s^2
<span>373.2 km
The formula for velocity at any point within an orbit is
v = sqrt(mu(2/r - 1/a))
where
v = velocity
mu = standard gravitational parameter (GM)
r = radius satellite currently at
a = semi-major axis
Since the orbit is assumed to be circular, the equation is simplified to
v = sqrt(mu/r)
The value of mu for earth is
3.986004419 Ă— 10^14 m^3/s^2
Now we need to figure out how many seconds one orbit of the space station takes. So
86400 / 15.65 = 5520.767 seconds
And the distance the space station travels is 2 pi r, and since velocity is distance divided by time, we get the following as the station's velocity
2 pi r / 5520.767
Finally, combining all that gets us the following equality
v = 2 pi r / 5520.767
v = sqrt(mu/r)
mu = 3.986004419 Ă— 10^14 m^3/s^2
2 pi r / 5520.767 s = sqrt(3.986004419 * 10^14 m^3/s^2 / r)
Square both sides
1.29527 * 10^-6 r^2 s^2 = 3.986004419 * 10^14 m^3/s^2 / r
Multiply both sides by r
1.29527 * 10^-6 r^3 s^2 = 3.986004419 * 10^14 m^3/s^2
Divide both sides by 1.29527 * 10^-6 s^2
r^3 = 3.0773498781296 * 10^20 m^3
Take the cube root of both sides
r = 6751375.945 m
Since we actually want how far from the surface of the earth the space station is, we now subtract the radius of the earth from the radius of the orbit. For this problem, I'll be using the equatorial radius. So
6751375.945 m - 6378137.0 m = 373238.945 m
Converting to kilometers and rounding to 4 significant figures gives
373.2 km</span>
Explanation:
If the size and direction of the forces on the object are exactly balanced , then there is no net force acting on the object
You performed 0 work for the fact that work means the distance of movement made on an object not the amount of force it is exposed to. 0 work because it didn't move
