A wooden block is sitting on an inclined plane near the bottom. The student gave the block a flick and it moved up the inclined
1 answer:
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Answer:
Part a)
Part b)
Part c)
Part d)
Part e)
Part f)
Part g)
Explanation:
Initial speed of the launch is given as
initial speed =
angle = degree
Now the two components of the velocity
similarly we have
Part a)
Now we know that horizontal range is given as
maximum height is given as
so we have
time of flight is given as
Part b)
Now the speed of the ball in x direction is always constant
so at the peak of its path the speed of the ball is given as
Part c)
Initial vertical velocity is given as
Part d)
Initial speed is given as
so we will have
Part e)
Angle of projection is given as
Part f)
If we throw at same speed so that it reach maximum height
then the height will be given as
Part g)
For maximum range the angle should be 45 degree
so maximum range is
1) Current: 4.5 A
2) Time taken: 4.7 s
Explanation:
1)
The electric current intensity is defined as the rate at which charge flows in a conductor; mathematically:
where
I is the current
q is the amount of charge passing a given point in a time t
For the wire in this problem, we have
q = 9.0 C is the amount of charge
t = 2.0 s is the time interval
Solving for I, we find the current:
2)
To solve this problem, we can use again the same formula
where
I is the current
q is the amount of charge passing a given point in a time t
In this problem, we have:
I = 3.0 A (current)
q = 14.0 C (charge)
Therefore, the time taken for the charge to move past a particular spot in the wire is
Learn more about electric current:
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