Answer:
b) the collisions between molecules will increase and tge pressure will increas
Answer:
The speed at which she threw the marshmallow is approximately 4.76 m/s
Explanation:
The given in formation are;
The range in which the marshmallow was thrown = 2 m (The location of her friend)
The angle at which the marshmallow was thrown = 30 degrees
The horizontal range is given by the following formula;
![R = \dfrac{u^2 \times sin(2\cdot \theta)}{g}](https://tex.z-dn.net/?f=R%20%3D%20%5Cdfrac%7Bu%5E2%20%5Ctimes%20sin%282%5Ccdot%20%5Ctheta%29%7D%7Bg%7D)
Where;
R = The range = 3 m
u = The initial velocity
θ = The angle at which the marshmallow was thrown = 30°
g = The acceleration due to gravity = 9.81 m/s²
By substitution, we have;
![2 = \dfrac{u^2 \times sin(2\times 30)}{9.81} = \dfrac{u^2 \times sin(60)}{9.81}](https://tex.z-dn.net/?f=2%20%3D%20%5Cdfrac%7Bu%5E2%20%5Ctimes%20sin%282%5Ctimes%2030%29%7D%7B9.81%7D%20%3D%20%20%5Cdfrac%7Bu%5E2%20%5Ctimes%20sin%2860%29%7D%7B9.81%7D)
![\therefore u^2 = \dfrac{ 2 \times 9.81}{sin(60)} = \dfrac{u^2 \times sin(60)}{9.81} \approx 22.66](https://tex.z-dn.net/?f=%5Ctherefore%20u%5E2%20%3D%20%5Cdfrac%7B%202%20%5Ctimes%209.81%7D%7Bsin%2860%29%7D%20%3D%20%20%5Cdfrac%7Bu%5E2%20%5Ctimes%20sin%2860%29%7D%7B9.81%7D%20%5Capprox%20%2022.66)
u ≈ √(22.66) ≈ 4.76 m/s
u ≈ 4.76 m/s
The speed at which she threw the marshmallow ≈ 4.76 m/s.
Answer:
The interactions occur when waves pass from one medium to another. Besides bouncing back like an echo, waves may bend or spread out when they strike a new medium. These three ways that waves may interact with matter are called reflection, refraction, and diffraction.
Explanation:
Answer:
Law of Motion/ Law of Inertia
Explanation:
Objects at rest stay at rest unless you're the one to move it.
The glacier with move approximately 1665.1cm after 6.6 years