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3 years ago

How does gravity affect our solar system?

1 answer:

5 0

The attraction of an object to something else with mass. What is the solar
system? The solar system is the alignment of planets around the sun. All the planets are in orbit around the sun. Our Solar System There are also Asteroids, comets, moons, and other forms of matter throughout space So What is the major role of gravity in our solar system? Holding Everything In Place. Without gravity a lot of things
<span>would go wrong. If there was no gravitational force on planets, people would float off into the sky.</span>

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Which of the following changes will always increase the efficiency of a thermodynamic engine? Choose all correct statements.

Ilya [14]

Answer:B,C,D

Explanation:

Thermodynamic efficiency is given by

$\eta =1-\frac{T_C}{T-H}$

$\eta$ efficiency can be increased by Keeping $_c$ constant and increasing $T_H$

Keeping $T_H$ constant and decreasing $T_c$

by increasing $\Delta T=T_H-T_c$

by decreasing $\frac{T_C}{T_H}$ ratio

5 0

3 years ago

Read 2 more answers

Correct Number Formats Numbers may be entered in several formats - including scientific notation and numerical expressions.

Illusion [34]

Answer:

a. Valid

b. Invalid

c. Invalid

d. Invalid

e. Valid

f. Valid

g. Invalid

Explanation:

Since, it follows all the four rules,

Therefore, this number is <u>Valid</u>

It uses upper case E, instead of lower case e.

Therefore, it is <u>Invalid</u>

It violates third rule for including unit.

Therefore, it is <u>Invalid</u>

It violates the first rule. As, there is a space between 6 and e. While in the example given in question, there is no gap.

Therefore, it is <u>Invalid</u>

Since, it follows all the four rules,

Therefore, this number is <u>Valid</u>

Since, it follows all the four rules,

Therefore, this number is <u>Valid</u>

It violates third rule for including unit.

Therefore, it is <u>Invalid</u>

6 0

3 years ago

A point charge q1=+5.00nC is at the fixed position x=0, y=0, z=0. You find that you must do 8.10×10−6J of work to bring a second

Maru [420]

The value of the second charge is 1.2 nC.

<h3>Electric potential</h3>

The work done in moving the charge from infinity to the given position is calculated as follows;

W = Eq₂

E = W/q₂

<h3>Magnitude of second charge</h3>

The magnitude of the second charge is determined by applying Coulomb's law.

$E = \frac{kq_2}{r^2} \\\\\frac{kq_2}{r^2} = \frac{W}{q_2} \\\\kq_2^2 = Wr^2\\\\q_2^2 = \frac{Wr^2}{k} \\\\q_2 = \sqrt{\frac{Wr^2}{k} } \\\\q_2 = \sqrt{\frac{(8.1 \times 10^{-6}) \times (0.04)^2}{9\times 10^9} } \\\\q_2 = 1.2 \times 10^{-9} \ C\\\\q_2 = 1.2 \ nC$