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Alla [95]
3 years ago
7

According to Kepler's harmonic law, Neptune would have a _________ orbit around the Sun than Mercury.

Physics
2 answers:
N76 [4]3 years ago
8 0

Slower

Explanation:

Kepler's harmonic law (also called Kepler's third law) states that:

"The cube of the radius of the orbit of a planet around the sun is proportional to the square of its period of revolution"

In formula, this can be written as

\frac{r^3}{T^2}=const.

where

r is the radius of the orbit

T is the orbital period

const. is a constant number, which is the same for all the planets orbiting the sun

By looking at the equation, we can see that the further a planet from the sun, the larger its orbital period: this means that the further planet will have a slower orbit. In this problem, we have to compare Neptune and Mercury: since Neptune is further from the sun than Mercury, also its orbital period will be larger, and therefore Neptune would have a slower orbit around the Sun than Mercury.

chubhunter [2.5K]3 years ago
3 0
Neptune would have a slower orbit i just did this

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if a scientist is comparing two different earthquake waves and notices that the amplitude is the same for both, but earthquake 1
olganol [36]
The one with the higher frequency has more energy than the other.
5 0
3 years ago
Use words in the box to complete the diagram, and the definitions below it. Some words will be used
Masteriza [31]

The correct words to fill the given blanks would be as follows:

- Peak

- Trough

- Equilibrium Line

- Oscillation

- Frequency, Hertz

- Period, seconds

  • The "peak" is denoted as the highest or maximum point that the wave attains while 'Trough' is characterized as the base of the wave.
  • The 'equilibrium line' is characterized as the extent to which the wave flattens or compresses.
  • Oscillation is defined as the process in which an object moves in the "back and forth motion."
  • Frequency is the amount of occurrences that waves travel in a second which is denoted in the terms of Hertz.
  • Lastly, period is the duration required by wave to accomplish one motion is denoted in terms of seconds.
  • Amplitude is the breadth or magnitude of the waves.

Learn more about "Oscillation" here:

brainly.com/question/9820984

7 0
2 years ago
Read 2 more answers
An asteroid has acquired a net negative charge of 149 C from being bombarded by the solar wind over the years, and is currently
bearhunter [10]

Answer:

93.125 × 10^(19)

Explanation:

We are told the asteroid has acquired a net negative charge of 149 C.

Thus;

Q = -149 C

charge on electron has a value of:

e = -1.6 × 10^(-19) C

Now, for us to determine the excess electrons on the asteroid, we will just divide the net charge in excess on the asteroid by the charge of a single electron.

Thus;

n = Q/e

n = -149/(-1.6 × 10^(-19))

n = 93.125 × 10^(19)

Thus, it has 93.125 × 10^(19) more electrons than protons

5 0
3 years ago
A horizontal disk with a radius of 10 cm rotates about a vertical axis through its center. The disk starts from rest at t = 0 an
Tom [10]

Answer:

0.69s

Explanation:

10 cm = 0.1 m

Let t be the time that radial and tangential components of the linear acceleration of a point on the rim be equal in magnitude. At that time we have the angular velocity would be

\omega = \alpha t = 2.1 t

And so the radial acceleration is

a_r = \omega^2 r = (2.1t)^2 r = 2.1^2 t^2 * 0.1= 0.441 t^2 m/s^2

The tangential acceleration is always the same since angular acceleration is constant:

a_t = \alpha * r = 2.1 * 0.1 = 0.21 m/s^2

For these 2 quantities to be the same

a_r = a_t

0.441 t^2 = 0.21

t^2 = 0.21/0.441 = 0.4762

t = \sqrt{0.4762} = 0.69 s

6 0
3 years ago
An electron has a constant acceleration of +3.3 m/s2. at a certain instant its velocity is +8.6 m/s. what is its velocity (a) 2.
Citrus2011 [14]
Hello!


The velocity function is:

\mathsf{V = V_0 + at}\\ \\ \mathsf{V = 8.6 +3.3t}


a) 2.3 s earlier, we can make t = -2.3 s, in relation to our initial time:

\mathsf{V = 8.6 + 3.3\cdot(-2.3)}\\ \\ \mathsf{V = 8.8-7.59}\\ \\ \boxed{\mathsf{V = 1.21 \ m/s}}

b) Now we can make t = 2.3 s:

\mathsf{V = 8.6 + 3.3\cdot2.3}\\ \\ \mathsf{V = 8.6 + 7.59}\\ \\ \boxed{\mathsf{V = 15.59 \ m/s}}
7 0
3 years ago
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