Answer:
O2 - exhibits dispersion forces as its strongest intermolecular force.
Explanation:
Generally speaking, all biatomic homonuclear molecules, such as N2, O2, F2, do NOT have any dipole moment: the distibution of the nuclear clouds is symmetrical. They are non-polar.
For what concerns heteronuclear molecules, it depends on their geometry.
Dispersion force ( Van der Waal)< dipole dipole < hydrogen bond
Intermolecular forces are forces of attraction between molecules/atoms based mainly on the idea of like charges repel and opposite charges attract.
Based on the polarity of the substance, the type of intermolecular forces existing between substance may be different.
<h3>Answer: sorry i don't know what the answer that question </h3>
Answer:
you would need to multiply 50 times 2 wich is 100 so i beleive its 100
Explanation:
There are 115 protons in the element 115 and due to the large number of protons, the element does not exist in nature.
Also, the element can not be isolated in nature that is IUPAC had to require an independent confirmation of the element.
<h3>What is element 115?</h3>
We know that the periodic table is an arrangement of the atoms in order of increasing atomic number. We know that the larger the atomic number of the element, the less likely that the element would be stable in nature. The element that have been named 115 is called Moscovium and was discovered in Moscow as a product of a radioactive experiment. The number of protons in element 115 is 115 protons
Generally, the element number 115 does not exist in nature because if the proton number in an element exceeds 82, the repulsion between the protons would make it almost impossible for the nucleus to be a stable nucleus.
The reason why IUPAC had to request an independent confirmation of the element is because it does not exist in nature.
Learn more about element 115:brainly.com/question/27914234
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To solve for the problem above, note that the given compound is not charged which indicates that the sum of the oxidation numbers of atoms present is zero. The oxidation number of H is +1 and that of O is -2. Let x be the oxidation number of N and the generated equation is,
+1 + x + (-2)(2) = 0
From the equation the value of x is 3. Therefore, the oxidation number of N is 3.
