Question

Liquid octane CH3CH26CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is the theoretical yield of water formed from the reaction of 72.0g of octane and 144.g of oxygen gas

Answer 1

Answer:

Explanation:

2CH₃(CH₂)₆CH₃ + 25O₂ = 16CO₂ + 18H₂O.

2 moles                25 moles                18 moles

mol weight of octane = 114

72 g of octane = 72 / 114 = .6316 moles

144 g of oxygen = 144 / 32 = 4.5 moles of oxygen.

2 moles of octane reacts with 25 moles of oxygen

.6316 moles of octant will react with 25 x .6316 / 2 moles of oxygen

= 7.895 moles

So oxygen is the limiting reagent

25 moles oxygen produces 18 moles water

4.5 moles of water produces 18 x 4.5 / 25 moles of water

= 3.24 moles of water

= 3.24 x 18 grams of water

= 58.32 grams of water .