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oksano4ka [1.4K]
3 years ago
13

Can you share a strategy For multiplying?

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
8 0

Answer:

Step-by-step explanation:

It's like the same thing for adding. For example if you have 3 x 4. You can add 3 four times or you can add 4 three times. Like this.

3 + 3 + 3 + 3 = 12 because you know 3 + 3 =6 and 6 + 6 equals 12.

OR

4 + 4 + 4 = 12 because you know 4 + 4 = 8 and 8 + 4 equals 12.

I hope this helped. I am sorry if I didn't do much of help. Have a wonderful day.

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I need help pls help
Sauron [17]

Answer:

I could be wrong, but I think it's D

8 0
3 years ago
Can u guy give me the AWNSER for number 3 or which ever on u know the Awnser to plz
FinnZ [79.3K]
3. Three and four tenths. 3+0.4=3.4
4. Two and fifty-one hundredths. 2+0.51=2.51
5. 8/10
6. 0.05
7. 46/100
8. 0.6
9. 9/10
10. 0.35

1 and 2 are correct btw
3 0
3 years ago
Can someone PLEASE help me with THIS QUESTION
s2008m [1.1K]

Answer:

3.5

Step-by-step explanation:

you will go like sum of frequency multiplied by score divided by sum of frequency

4 0
3 years ago
The table shows the steps for solving the given inequality for x.
slavikrds [6]

Given inequality -3(4-6x) < x+5.

We have -3 in front of Parenthesis.

That represents multiplication of -3 and Parenthesis.

The multiplication of Parenthesis could be done by applying distributive property.

On distributing, we get

-12+18x < x+5

x is added on right side of the inequality. The reverse operation of addition is subtraction. So we need to subtract x from both sides, we get

-12+18x-x < x-x+5

-12+17x < 5

Now, we need to get rid -12 from left side.

So, we need to apply addition property of equality, we need to add 12 on both sides, we get

-12+12+18x < x+5+12

17x < 17

We need to get rid 17 from left side. So we need to apply division property of equality.

On dividing both sides by 17, we get

17x/17 < 17/17

x<1.

8 0
3 years ago
Please help I’m really confused and need to learn this
egoroff_w [7]

Answer:

2.

Step-by-step explanation:

For #2, another way to word this question is: For which of the following trig functions is π/2 a solution? Well, go through them one by one. If you plug π/2 into sinθ, you get 1. This means that when x is π/2, y is 1. Try and visualize that. When y is 1, that means you moved off the x-axis; so y = sinθ is NOT one of those functions that cross the x-axis at θ = π/2. Go through the rest of them. For y = cos(π/2), you get 0. At θ = π/2, this function crosses the x-axis. For y = tanθ, your result is undefined, so that doesn't work. Keep going through them. You should see that y = secθ is undefined, y = cscθ returns 1, and y = cotθ returns 0. If you have a calculator that can handle trig functions, just plug π/2 into every one of them and check off the ones that give you zero. Graphically, if the y-value is 0, the function is touching/crossing the x-axis.

Think about what y = secθ really means. It's actually y = 1/(cosθ), right? So what makes a fraction undefined? A fraction is undefined when the denominator is 0 because in mathematics, you can't divide by zero. Calculators give you an error. So the real question here is, when is cosθ = 0? Again, you can use a calculator here, but a unit circle would be more helpful. cosθ = π/2, like we just saw in the previous problem, and it's zero again 180 degrees later at 3π/2. Now read the answer choices.

All multiples of pi? Well, our answer looked like π/2, so you can skip the first two choices and move to the last two. All multiples of π/2? Imagine there's a constant next to π, say Cπ/2 where C is any number. If we put an even number there, 2 will cut that number in half. Imagine C = 4. Then Cπ/2 = 2π. Our two answers were π/2 and 3π/2, so an even multiple won't work for us; we need the odd multiples only. In our answers, π/2 and 3π/2, C = 1 and C = 3. Those are both odd numbers, and that's how you know you only need the "odd multiples of π/2" for question 3.

6 0
3 years ago
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