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2 years ago

Disagree or agree n provide evidence !!! pls n thank you

Chemistry

1 answer:

stealth61 [152]2 years ago

5 0

Answer: True

Explanation: There are many different types of reactions that can occur during a chemical reaction, a substance dissolving is one of them! often you will notice the following: fizzling, bubbles, color change, odor being produced, smoke. etc.

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What is the gram formula mass of Glycine , NH2CH2COOH

dem82 [27]

N=14
H= 1(5)= 5
C=12(2)=24
O=16(2)=32

= 75

6 0

2 years ago

How many moles are found in 133 g of Mg3 N2

konstantin123 [22]

Magnesium nitride weighs 100.95 g/mol

133/100.95 = 1.32 mols

7 0

2 years ago

Read 2 more answers

Consider the second-order reaction:

kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

Explanation:

$2HI(g)\rightarrow H_2(g)+I_2(g)
$

Rate Law: $k[HI]^2
$

Rate constant of the reaction = k = $6.4\times 10^{-9} L/mol s$

Order of the reaction = 2

Initial rate of reaction = $R=1.6\times 10^{-7} Mol/L s$

Initial concentration of HI = $[A_o]$

$1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2$

$[A_o]=5 mol/L$

Final concentration of HI after t = [A]

t = $4.53\times 10^{10} s$

Integrated rate law for second order kinetics is given by:

$\frac{1}{[A]}=kt+\frac{1}{[A_o]}$

$\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}$

$[A]=0.00345 mol/L$

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

5 0

3 years ago

. What happens the pH of an acid solution as a base is added?

Dmitrij [34]

As a base is added to an acidic solution, the H+ ions in solution that make it acidic are slowly neutralized into water (via OH-, the base). As these ions are converted into water the concentration of them decreases, so the pH decreases, as they are directly related.

Hope this helps!

3 0

3 years ago

Number of moles in 31.99g O2 <br> And 176.8g NaCl

sergey [27]

#O_2

$\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}$