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frosja888 [35]
3 years ago
9

The position x, in meters, of an object is given by the equation:

Physics
1 answer:
LenaWriter [7]3 years ago
3 0

Answer:

The SI units of A, B and C are :

m,\ m/s\ and\ m/s^2                  

Explanation:

The position x, in meters, of an object is given by the equation:

x=A+Bt+Ct^2

Where

t is time in seconds

We know that the unit of x is meters, such that the units of A, Bt and Ct^2 must be meters. So,

  • A=m
  • bt=m

b=\dfrac{m}{s}=m/s

  • Ct^2=m

C=m/s^2

So, the SI units of A, B and C are :

m,\ m/s\ and\ m/s^2

So, the correct option is (B).

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Calculate the angular velocity of the neptune (orbital period of 165 earth period) in its orbit around the sun.
ludmilkaskok [199]
The correct answer is: Angular velocity =  1.208 * 10^{-9} rad/s

Explanation:
The angular velocity is given as:
ω = \frac{2\pi}{T} --- (1)

Where T = 165 * (365 days) * (24 hours/day) * (60 minutes/hour) * (60 seconds/minute) = 5203440000 s

Plug in the value in (1):
ω = \frac{2\pi}{5203440000} = 1.208 * 10^{-9} rad/s
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3 years ago
Please I need help with these 2 questions. Thank you.
Lemur [1.5K]
First one is D and Second one is B
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4 years ago
A 38.5 kg man is in an elevator
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I’m not too sure but I think it’s 8,91 m/s2
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3 years ago
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 152 om and makes an angl
aliya0001 [1]

Answer:

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement

Explanation:

We find the x-y components for the given vectors:

i:  unit vector in x direction

j:unit vector in y direction

D₁: Displacement Vector 1

D₂: Displacement Vector 2

R= resulta displacement vector

D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j

D₂= -D₂(i)-D₂(j)

R=  131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j

We propose the vector equation for sum of vectors:

D₁+ D₂= R

-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j

-51.99i+D₂x(i)=103.23i

D₂x=103.23+51.99=155.22 cm

+142.83j-D₂y(j) =+80.65j

D₂y=142.83-80.65=62.18 cm

Magnitude and direction of the second displacement

D_{2} =\sqrt{(D_{x})^{2} +(D_{y} )^{2}  }

D_{2} =\sqrt{(155.22)^{2} +(62.18 )^{2}  }

D₂= 167.21 cm

Direction of the second displacement

\beta = tan^{-1} \frac{D_{y}}{D_{x} }

\beta = tan^{-1} \frac{62.18}{155.22 }

β= 21.8°

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement

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4 years ago
What replaces a cold current that sinks to the ocean floor?
FrozenT [24]
Well simple the warm water then replaces the cold current that sinks to the ocean floor.
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3 years ago
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