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expeople1 [14]
3 years ago
5

A force of 29.4 N is required to pull a 100 kg ice block at constant speed along an ice surface. Find the coefficient of kinetic

friction for ice on ice.
Physics
1 answer:
mestny [16]3 years ago
6 0

Answer:

The value is  \mu_k  = 0.03

Explanation:

From the question we are told that

  The force applied on the ice is F = 29.4 N

   The mass of the ice block is  m = 100 \  kg

Generally for the ice block to move at constant speed , the force applied on it must be equal to the kinetic frictional force which is mathematically represented as

         F_F =  m* g *  \mu_k

=>      F = F_F = m* g * \mu_k

=>      29.4 =  100 * 9.8 * \mu_k

=>       \mu_k  = 0.03

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The maximum wavelength that an electromagnetic wave can have and still eject electrons from a metal surface is 542 nm. What is t
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2.295 eV

Explanation:

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5 0
3 years ago
You charge an initially uncharged 89.9-mf capacitor through a 30.5-ω resistor by means of a 9.00-v battery having negligible int
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<span>1) The differential equation that models the RC circuit is :

(d/dt)V_capacitor </span>+ (V_capacitor/RC)​ = (V_source/<span>RC)​​</span>

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2)
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