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Mamont248 [21]
3 years ago
15

Calculate volume of carbon dioxide gas if the mass is 88.0 g at 20.0°C and 950mmHg

Chemistry
1 answer:
aivan3 [116]3 years ago
7 0

Answer:

Tam tam fdjknf

Explanation:

ttgtsrttrg

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Write the name and formula for the chemical substance which is produced in most acid-base neutralization reactions
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Acid + base gives you salt and H2O
7 0
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The density of a metal cube is 8 x103 kg/m3. Convert
Rom4ik [11]

Answer:

Explanation:

[peirod4

4 0
3 years ago
Which element is the excess reagent when 3.00 moles of Mg is ignited in 2.20 moles of pure oxygen
Artyom0805 [142]

Answer:

Oxygen is in excess.

Explanation:

The coefficients of the balanced equation create a mole ratio that shows the ratio of how many reactants are used up and products are created.  

The mole ratio of Mg to O2 in this equation is 2:1, which means that for every two moles of Mg used, there will be 1 mole of O2 used.

If we have 3.00 moles of Mg, we will only need 1.5 moles of oxygen to completely burn the Mg. Therefore, when all 3.00 moles of Mg are used, there will still be some of the 2.20 moles of oxygen remaining.

7 0
2 years ago
Which type of molecule is propanol? <br> A. Alcohol <br> B. Aldehyde <br>C. Ketone <br>D. Amine ​
snow_lady [41]

Answer:

B.

Explanation:

Propanal is an organic compound with the formula CH3CH2CHO. Aldehyde is colorless, flammable and a slightly fruity odor.

8 0
2 years ago
what is the concentration of an NaOH solution that requires 50 mL of a 1.25 M H2SO4 solution to neutralize 78.0 ml of NaOH​
Dimas [21]

Answer:

  • The answer is the concentration of an NaOH = 1.6 M

Explanation:

The most common way to solve this kind of problem is to use the formula  

  • C₁ * V₁ = C₂ * V₂

In your problem,

For NaOH

C₁ =??     v₁= 78.0 mL = 0.078 L

For H₂SO₄

C₁ =1.25 M     v₁= 50.0 mL = 0.05 L

but you must note that for the reaction of NaOH with H₂SO₄

2 mol of NaOH raect with 1 mol H₂SO₄

So, by applying in above formula

  • C₁ * V₁ = 2 * C₂ * V₂
  • (C₁ * 0.078 L) = (2*  1.25 M * 0.05 L)
  • C₁ = (2*  1.25 M * 0.05 L) / (0.078 L) = 1.6 M  

<u>So, the answer is the concentration of an NaOH = 1.6 M</u>

3 0
3 years ago
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