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2 years ago

What does conserving mass mean in a chemical equation?

Chemistry

2 answers:

luda_lava [24]2 years ago

8 0

The answer is C. There is equal number of each type of atom on the reactant side and product side.

I just did test!

Hope it helps :)

AleksandrR [38]2 years ago

4 0

I would say that what conserving mass in a chemical equation means is that C. There is equal number of each type of atom on the reactant side and product side.
The equation is equal and no material is lost or gained.

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Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O . Suppose

Slav-nsk [51]

Answer:

The minimum mass of octane that could be left over is 43.0 grams

Explanation:

Step 1: Data given

Mass of octane = 73.0 grams

Mass of oxygen = 105.0 grams

Molar mass octane = 114.23 g/mol

Molar mass oxygen = 32.0 g/mol

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate the number of moles

Moles = mass / molar mass

Moles octane = 73.0 grams / 114.23 g/mol

Moles octane = 0.639 moles

Moles O2 = 105.0 grams / 32.0 g/mol

Moles O2 = 3.28 moles

Step 4: Calculate the limiting reactant

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

O2 is the limiting reactant. It will completely be consumed. (3.28 moles). There will react 3.28 / 12.5 = 0.2624 moles. There will remain 0.639 - 0.2624 = 0.3766 moles octane

Step 5: Calculate mass octane remaining

Mass octane = moles * molar mass

Mass octane = 0.3766 moles * 114.23 g/mol

Mass octane = 43.0 grams

The minimum mass of octane that could be left over is 43.0 grams

3 0

3 years ago

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Svetach [21]

Answer:

distance between them , and mass of the objects

Explanation:

the further away a object is the weaker the gyrational pull is, and imagine lifting a anvil above your head, the anvil weight push's down upon you pulling.

4 0

2 years ago

Read 2 more answers

Which is one way that minerals crystallize from materials dissolved in water?

Andreyy89

Answer:

the second answer its science behind it

3 0

2 years ago

Read 2 more answers

When a 1.00-g sample of methane gas was burned with excess oxygen in the calorimeter, the temperature increased by 7.3°C. When

Advocard [28]

Answer:

The energies of combustion (per gram) for hydrogen and methane are as follows: Methane = 82.5 kJ/g; Hydrogen = 162 kJ/g

Note: The question is incomplete. The complete question is given below:

To compare the energies of combustion of these fuels, the following experiment was carried out using a bomb calorimeter with a heat capacity of 11.3 kJ/℃. When a 1.00-g sample of methane gas burned with

excess oxygen in the calorimeter, the temperature increased by 7.3℃. When a 1.00 g sample of hydrogen gas was burned with excess oxygen, the temperature increase was 14.3°C. Compare the energies of combustion (per gram) for hydrogen and methane.

Explanation:

From the equation of the first law of thermodynamics, ΔU = Q + W

Since there is no expansion work in the bomb calorimeter, ΔU = Q

But Q = CΔT

where C is heat capacity of the bomb calorimeter = 11.3 kJ/ºC; ΔT = temperature change

For combustion of methane gas:

Q per gram = ( 11.3 kJ/ºC * 7.3°C)/1.0g

Q = 83 kJ/g

For combustion of hydrogen gas:

Q per gram = ( 11.3 kJ/ºC * 14.3°C)/1.0g

Q = 162 kJ/g

3 0

3 years ago

How mant liters at STP are in 0.575 moles of Kr

gizmo_the_mogwai [7]

Answer:

12.9 L Kr

General Formulas and Concepts:

Chemistry - Gas Laws

Using Dimensional Analysis
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

Step 1: Define

0.575 mol Kr

Step 2: Identify Conversions

1 mol= 22.4 L at STP

Step 3: Convert

$0.575 \ mol \ Kr(\frac{22.4 \ L \ Kr}{1 \ mol \ Kr} )$ = 12.88 L Kr

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

12.88 L Kr ≈ 12.9 L Kr

8 0

3 years ago