Answer:
trans-1,3-pentadiene is more stable than 1,4-pentadiene due to presence of a conjugated double bond.
Explanation:
Here, 
H(hydrogenated pdt.) is same for both 1,4-pentadiene and 1,3-pentadiene as they both produce pentane after hydrogenation
H(diene) depends on stability of diene.
More stable a diene, lesser will be it's H(diene) value (more neagtive).
trans-1,3-pentadiene is more stable than 1,4-pentadiene due to presence of a conjugated double bond.
Hence, 
is higher (less negative) for trans-1,3-pentadiene
I am a blacksmith, I would know this one. Alright... Aluminum, has a great shine to it, and it looks like silver... Same with tin, except aluminum is super shiny and sleek, while tin has a dull shine to it. Steel, is flat (color-wise), and it has a slight shine to it.
You can find what type of metal it is by color, shine, light reflectance, dullness, and several other properties. Hope I helped you! :)
The reactants of the reaction of single replacement that produces ZnCl₂ and H₂ is Zn + 2HCl
Explanation
In a single replacement reaction is a chemical reaction whereby an element react with compound and take the place of another element in that compound.
zn displaces H from HCl to form ZnCl₂ and H₂ according to below equation.
Zn +2HCl → ZnCl₂ + H₂
Answer:
20.8 Lof NH₃ are needed for the reaction
Explanation:
This is the reaction:
4 NH₃ + 6 NO → 5N₂ + 6H₂O
and the info. we need
Ammonia density = 0,00073 g/mL
Let's determine the moles of NO at STP by the Ideal Gases Law equation
P . V = n . R .T
1atm . 30L = n . 0.082 . 273K
(1atm . 30L) / (0.082 . 273K) = n → 1.34 moles of NO
Let's find out the amount of ammonia that should react
6 mol of NO react with 4 mol of ammonia
1.34 mol of NO will react with (1.34 .4)/6 = 0.893 moles of ammonia
Molar mass NH₃ = 17 g/m
0.893 mol . 17 g/m = 15.19 g of ammonia
Ammonia density = 0,00073 g/mL = NH₃ mass / NH₃ volume
0,00073 g/mL = 15.19 g / NH₃ volume
NH₃ volume = 15.19 g / 0,00073 g/mL → 20805.5 mL ⇒ 20.8 L
