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3 years ago

How would a chart of mid-17th century religious beliefs differ from this chart?

Physics

2 answers:

tino4ka555 [31]3 years ago

4 0

Answer:

The correct answer is B) Fewer people would identify as an atheist because people were not willing to share alternative religious beliefs publically.

Explanation:

A chart of mid-17th-century religious beliefs differs from this chart in that Fewer people would identify as an atheist because people were not willing to share alternative religious beliefs publically.

In the 1600s, people did not have total freedom of speech if they had any. The church had a tremendous influence in the life of people and religious beliefs defined societies and families. The Church exerted its power and influence in many aspects of the people's lives and something out of the purview of the church or different to the religious beliefs of the Church was considered to be sacrilegious. The Church prosecuted people for being against the Church, so people of that time preferred to say that they were religious people supporting the church. Being an atheist was not really an option in the 17th century.

<u><em>Hope this helps!!</em></u>

meriva3 years ago

3 0

Answer: The first one

Fewer people would identify as atheist because people who did not identify with the official religion did not say so out loud.

Explanation:

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tatyana61 [14]

Answer:

0.76

Explanation:

we are given:

radius (r) =5.7 m

speed (s) = 1 revolution in 5.5 seconds

acceleration due to gravity (g) = 9.8 m/s^{2}

coefficient of friction (Uk) = ?

we can get the minimum coefficient of friction from the equation below

centrifugal force = frictional force

m x r x ω^{2} = Uk x m x g

r x ω^{2} = Uk x g

Uk = $\frac{ r x ω^{2} }{g}$

where ω (angular velocity) = $\frac{2π}{time}$

= $\frac{2π }{5.5}$ = 1.14

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3 years ago

Find the wavelength in meters for a transverse mechanical wave with an amplitude of 10 cm and a radian frequency of 20π rad/s if

nydimaria [60]

Answer:

The wavelength of the wave is 20 m.

Explanation:

Given that,

Amplitude = 10 cm

Radial frequency $\omega = 20\pi\ rad/s$

Bulk modulus = 40 MPa

Density = 1000 kg/m³

We need to calculate the velocity of the wave in the medium

Using formula of velocity

$v=\sqrt{\dfrac{k}{\rho}}$

Put the value into the formula

$v=\sqrt{\dfrac{40\times10^{6}}{10^3}}$

$v=200\ m/s$

We need to calculate the wavelength

Using formula of wavelength

$\lambda =\dfrac{v}{f}$

$\lambda=\dfrac{v\times2\pi}{\omega}$

Put the value into the formula

$\lambda=\dfrac{200\times2\pi}{20\pi}$

$\lambda=20\ m$

Hence, The wavelength of the wave is 20 m.

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2 years ago

Holly puts a box into the trunk of her car. Later, she drives around an unbanked curve that has a radius of 48 m. The speed of t

LiRa [457]

Answer:

The minimum coefficient of friction is 0.544

Solution:

As per the question:

Radius of the curve, R = 48 m

Speed of the car, v = 16 m/s

To calculate the minimum coefficient of static friction:

The centrifugal force on the box is in the outward direction and is given by:

$F_{c} = \frac{mv^{2}}{R}$

$f_{s} = \mu_{s}mg$

where

$\mu_{s}$ = coefficient of static friction

The net force on the box is zero, since, the box is stationary and is given by:

$F_{net} = f_{s} - F_{c}$

$0 = f_{s} - F_{c}$

$\mu_{s}mg = \frac{mv^{2}}{R}$

$\mu_{s} = \frac{v^{2}}{gR}$

$\mu_{s} = \frac{16^{2}}{9.8\times 48} = 0.544$

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3 years ago

Processing Questions:

ser-zykov [4K]

Answer:

How was the result of your physical fitness test in Flexibility and muscular

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2 years ago

a speed swimmer love to race around the parks pine which is 25m around if she can swim 20 laps in 7200s what is her average spee

aleksley [76]

Answer:

the average speed of the swimmer is 0.069 m/s.

Explanation:

Given;

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total lap completed, = 20 laps

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The total distance completed by the swimmer = 20 x 25 = 500 m

The average speed of the swimmer = distance / time

= (500 m) / (7200 s)

= 0.069 m/s.

Therefore, the average speed of the swimmer is 0.069 m/s.

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2 years ago