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slava [35]
3 years ago
8

How would a chart of mid-17th century religious beliefs differ from this chart?

Physics
2 answers:
tino4ka555 [31]3 years ago
4 0

Answer:

The correct answer is B)  Fewer people would identify as an atheist because people were not willing to share alternative religious beliefs publically.

Explanation:

A chart of mid-17th-century religious beliefs differs from this chart in that Fewer people would identify as an atheist because people were not willing to share alternative religious beliefs publically.

In the 1600s, people did not have total freedom of speech if they had any. The church had a tremendous influence in the life of people and religious beliefs defined societies and families. The Church exerted its power and influence in many aspects of the people's lives and something out of the purview of the church or different to the religious beliefs of the Church was considered to be sacrilegious. The Church prosecuted people for being against the Church, so people of that time preferred to say that they were religious people supporting the church. Being an atheist was not really an option in the 17th century.

<u><em>Hope this helps!!</em></u>

meriva3 years ago
3 0

Answer: The first one

Fewer people would identify as atheist because people who did not identify with the official religion did not say so out loud.

Explanation:

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KE = 1/2 m v²

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20 Yards

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|            |

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7 0
3 years ago
Given one mole of diamond vs one mole of graphite,
grandymaker [24]

Answer:

The pressure is P= -  6.39*10^8Pa

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Explanation:

Generally Gibbs free energy is mathematically represented as

                   G = E + PV -TS

   Where  E is the enthalpy

               PV is the pressure volume energy (i.e PV energy)

                S  is the entropy

                T is the temperature

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         E + PV - TS = 0

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          P = \frac{TS-E}{V}

Now substituting 300 K for T , 2900 J  for E ,

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     P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}

         P= -  6.39*10^8Pa

The negative sign signifies the direction of the pressure

Given that  P = 1*0^5Pa

making T the subject

            T = \frac{PV+E}{S}

Substituting into the equation

            T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}

                T =1218.63 K

             

         

7 0
3 years ago
Read 2 more answers
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