Part a:
= 56
= 60
= 63
The quartiles are found by finding the medium of the data, and then the mediums of the two different data sets on either side of the medium. The is the overall medium, is the medium of the first half, and is the medium of the second half.
-> How is the medium found? When finding the medium we put the values in order least to greatest and pick the middle value.
[] See attached
Part b:
The range is 7.
The interquartile range is the range of numbers between and . In other words, it is 50% of the data, directly in the middle.
This becomes 63 - 56 = 7
Part c:
79 is an outlier.
It is an outlier because it is 1.5 above or below (in this case, above) the interquartile range.
-> 63 + (7 + 
) ≤ 79
-> 63 + 10.5 ≤ 79
-> 73.5 ≤ 79
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.
- Heather
Answer:
d= 7.32 mm
Explanation:
Given that
E= 110 GPa
σ = 240 MPa
P= 6640 N
L= 370 mm
ΔL = 0.53
Area A= πr²
We know that elongation due to load given as
A= 42.14 mm²
πr² = 42.14 mm²
r=3.66 mm
diameter ,d= 2r
d= 7.32 mm
I think D. liquid water moving along the surfac
Answer:
why did the parents let go of their child-
Explanation:
A 5 kg, because 90 / 18 is 5
Answer:
13.33 seconds
Explanation:
At maximum height, the equation of motion becomes:
<em> v = u + at</em>
Since the object was thrown vertically, the initial velocity (u) is zero and the acceleration (a) becomes the acceleration due to gravity (10 m/s2). The equation becomes:
<em>v = at</em>
<em>v = 480 k</em>m/hr = 133.333 m/s
10t = 133.333
t = 133.333/10
t = 13.33 seconds.
<em>The time for the ball thrown vertically with a velocity of 480 km/hr to reach the maximum height is </em><em>13.33 seconds</em><em>.</em>
