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torisob [31]
3 years ago
12

The screens show two sound waves that last the same amount of time. Which wave has a higher frequency? Explain your answer

Physics
1 answer:
SOVA2 [1]3 years ago
8 0

Answer:

Wave 1

Explanation:

Its a High frequency waves the high waves are closer to each other thme the lower ones

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Which of The following is the best example of water changing from a liquid to gas
expeople1 [14]

Answer:

There are no examples but this should be evaporation

Explanation:

4 0
3 years ago
An earth scientist who studies hydrosphere
ipn [44]
Oceanographer? I think that is what it is.
5 0
3 years ago
The vertical component of the projectile motion of an object depends on which of these? initial velocity or angel of trajectory
SVEN [57.7K]
It depends on both of them.

In fact, the projectile begins its motion with an initial velocity of v_0 and an angle of \alpha. On the y-axis (vertical direction), it is an accelerated motion with acceleration equal to -g (gravitational acceleration). The vertical velocity of the projectile at any time t is given by
v_y (t) = v_0 sin \alpha + gt
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3 0
4 years ago
What is the energy of a 9 kg brick that is
Tems11 [23]

Explanation:

formula for energy is k. e = ½mv²

m= 9

v= 75

k. e = ½×9×75 =337•5

6 0
3 years ago
Calculate the de Broglie wavelength of an electron accelerated from rest through a potential difference of (a) 100 V, (b) 1.0 kV
forsale [732]

Answer:

(a) \lambda=1.227\ A

(b) \lambda=0.388\ A

(c) \lambda=0.038\ A

Explanation:

Given that,

(a) An electron accelerated from rest through a potential difference of 100 V. The De Broglie wavelength in terms of potential difference is given by :

\lambda=\dfrac{h}{\sqrt{2meV} }

Where

m and e are the mass of and charge on an electron

On solving,

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

V = 100 V

\lambda=\dfrac{12.27}{\sqrt{100} }\ A

\lambda=1.227\ A

(b) V = 1 kV = 1000 V

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

\lambda=\dfrac{12.27}{\sqrt{1000} }\ A

\lambda=0.388\ A

(c) If V=100\ kV=10^5\ V

\lambda=\dfrac{12.27}{\sqrt{10^5} }\ A

\lambda=0.038\ A

Hence, this is the required solution.

7 0
3 years ago
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