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lawyer [7]
3 years ago
14

A rubber ball thrown at a speed of 5 m/s hit a flat wall and

Physics
1 answer:
velikii [3]3 years ago
5 0

Answer:

See the explanion below

Explanation:

Linear momentum is defined as the product of mass by velocity and can be calculated by the following equation.

P =m*v

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

When the ball hits the wall it receives a force for a very short time, this time and force value is known as momentum and can be calculated by the following expression.

-(m_{1}*v_{1}) + (F*t)=(m_{1}*v_{2})

where:

m₁ = mass of the ball [kg]

v₁ = 5 [m/s]

v₂ = 5 [m/s]

v₁ = v₂

F*t = Imp

Imp = (m_{1}*v_{1})+ (m_{1}*v_{2})\\Imp = 2*m*v_{1}

It can be said that the impulse is equal to 2 times the speed of throwing by the mass.

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Serggg [28]

Answer:

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

Explanation:

For this exercise let's use the relationship between momentum and momentum.

         I = F t = Δp

in this case the final velocity is zero

        F t = 0 -m v₀

        F = m v₀ / t

in order to answer the question we must assume that the two vehicles have the same mass and speed

concrete barrier

        F₁ = -p₀ / 0.1

        F₁ = - 10 p₀

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         F₂ = -p₀ / 1

let's look for the relationship of the forces

        F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

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Explanation:

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Temperature is the degree of hotness or coldness of body. It is power by heat energy between two bodies.

Heat generally flows from a body at high temperature to one at low temperature. When thermal equilibrium is established and both bodies have the same temperature, heat will stop to flow.

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