Question

A rubber ball thrown at a speed of 5 m/s hit a flat wall and

Answer 1

Answer:

See the explanion below

Explanation:

Linear momentum is defined as the product of mass by velocity and can be calculated by the following equation.

$P =m*v$

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

When the ball hits the wall it receives a force for a very short time, this time and force value is known as momentum and can be calculated by the following expression.

$-(m_{1}*v_{1}) + (F*t)=(m_{1}*v_{2})$

where:

m₁ = mass of the ball [kg]

v₁ = 5 [m/s]

v₂ = 5 [m/s]

v₁ = v₂

$F*t = Imp$

$Imp = (m_{1}*v_{1})+ (m_{1}*v_{2})\\Imp = 2*m*v_{1}$

It can be said that the impulse is equal to 2 times the speed of throwing by the mass.