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BARSIC [14]
3 years ago
15

Find the potential energy of a 2 kg ball 15 m in the air.

Physics
1 answer:
mart [117]3 years ago
8 0

Answer:

294.3 Joules

Explanation:

2kg*9.81m/s^2*Δ15=294.3J

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The cricket ball has a mass of 0.16kg and it hits the bat with a speed of 25 m/s. After being in contact with the bat for 0.0013
zavuch27 [327]

change in velocity is 3m/s,the force exterted by bat on ball is 4.8N and the acceleration is 30m/s².

<h3>Give  some difference between velocity and speed.</h3>

1) Speed is scalar quantity but velocity is vector quantity.

2) Speed is distance followed by an individual with respect to  time and velocity is displacement with respect to time .

1) final velocity- intial velocity

 25-22= 3m/s

2) The force is

F= ma

 . 0.16×30= 4.8N

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7 0
2 years ago
A student holding a 324Hz tuning fork approaches a wall at a speed of 6ms^(-1). The speed of sound in air is 336ms^(-1). What fr
Mashutka [201]

The frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.

<h3>Frequency detected by the student</h3>

The observed frequency is determined by applying Doppler effect;

f' = f₀(v + v₀)/(v)

where;

  • f' is the observed frequency
  • v is speed of sound
  • v₀ is the source speed
  • f₀ is the original frequency

f' = 342(6 + 336)/(336)

f' = 348.1 Hz

Thus, the frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.

Learn more about observed frequency here: brainly.com/question/10728818

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8 0
2 years ago
Two cars move down a hill at a constant velocity. Car c is much larger than car d. The car that has a greater momentum is:
babunello [35]

Answer:

C

Explanation:

When an object has a greater mass than the drag force pushing it back then it    is moving forward therefore making car C faster than car D. If car D was much smaller it wouldn't have enough mass to push past the drag force.

7 0
3 years ago
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Calculate the minimum frequency of ultrasound (in Hz) that will allow you to see details as small as 0.193 mm in human tissue. (
STatiana [176]

Answer:

f = 7.97 x 10⁶ Hz = 7.97 MHz

Explanation:

The speed of a wave is given by the following formula:

v = f\lambda

where,

v = speed of the ultrasound wave through human tissue = 1540 m/s

f = frequency of ultrasound wave required = ?

λ = wavelength of ultrasound waves = smallest detail required = 0.193 mm

λ = 0.193 mm = 1.93 x 10⁻⁴ m

Therefore,

1540\ m/s = f(1.93\ x\ 10^{-4}\ m)\\f = \frac{1540\ m/s}{1.93\ x\ 10^{-4}\ m}

<u>f = 7.97 x 10⁶ Hz = 7.97 MHz</u>

8 0
3 years ago
Plz guys answer my question
Sophie [7]

Answer:

Explanation:

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6 0
3 years ago
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