Find the potential energy of a 2 kg ball 15 m in the air.

2 rocks of different masses roll down a hill at the same speed which rock has more kinetic energy small one or big one ???

Sophie [7]

Kinetic energy depends on the mass and the speed of a moving object.

If the speeds are equal, then the rick with more mass has more kinetic energy.

5 0

2 years ago

Read 2 more answers

Estimate the magnitude of the electric field due to the proton in a hydrogen atom at a distance of 5.29 x 10-11 m, the expected

V125BC [204]

Would be A 1012 N/C because The magnitude of the electric field at distance r from a point charge q is E=k
e

q/r
2
, so
E=
(5.11×10
−11
m)
2

(8.99×10
9
N.m
2
/C
2
)(1.60×10
−19
C)

=5.51×10
11
N/C∼10
1
2N/C
making (e) the best choice for this question.

3 0

3 years ago

Add to

TEA [102]

Answer:

1) x_total = 2.7 km=2700 m, 2) t_total = 1926 s, 3) v_avg = 1.40 m / s

Explanation:

1) To solve this uniform velocity problem, we must find the displacement of each part and add them.

x_total = x₁ + x₂

x_total = 0.7 + 2.0

x_total = 2.7 km

2) how long does it take for this tour

truck

v = x₁ / t₁

t₁ = x₁ / v

t₁ = 0.7 / 20

t₁ = 0.035 h

Let's reduce the time to the SI system

t₁ = 0.035 h (3600 s / 1h) = 126 s

when he is walking

t₂ = 30 min (60 s / 1min) = 1800 s

the total time is

t_total = t₁ + t₂

t_total = 126 + 1800

t_total = 1926 s

3) the average velocity is defined as the displacement in the inerval between time

v_avg = x_total / t_total

v_avg = 2700/1926

v_avg = 1.40 m / s

8 0

3 years ago

A rock is thrown downward at a speed of 8.5 m/s and hits the ground 2.25 seconds later. From what height was the rock thrown? Wh

vekshin1

Answer:

The velocity and height is 31 m/s and 44.4 m respectively .

Explanation:

Given :

Initial speed of rock , u = 8.5 m/s .

Time taken to reach ground , t = 2.25 s .

Also , acceleration due to gravity is , $g=10\ m/s^2$ .

Now , to find the velocity when it hit ground .

Applying equation of motion :

$v=u+at\\v=8.5+10\times 2.25\\v=31\ m/s$

Also , height from which rock is thrown is given by :

$h=ut+\dfrac{at^2}{2}\\\\h=8.5\times 2.25+\dfrac{10\times 2.25^2}{2}\\\\h=44.4\ m$

Hence , this is the required solution .

7 0

3 years ago

A cylindrical tank of methanol has a mass of 70 kg and a volume of 75 L. Determine the methanol’s weight, density, and specific

dem82 [27]

Answer:

Weight=686.7N, $\rho=933kg/m^{3}$ , S.G.=0.933, F=17.5N

Explanation:

So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:

W=mg

so we can substitute the data the problem provided us with to get:

$W=70kg(9.81m/s^{2})$