Answer:
Option D - the moisture content at turbine exit will decrease
Explanation:
In an ideal rankine system, the phenomenon of superheating occurs at a state where the vapor state of the fluid is heated above its saturation temperature and the phase of the fluid is changed from the vapor phase to the gaseous phase.
Now, a vapour phase has two different substances at room temperature, whereas a gas phase consists of just a single substance at a defined thermodynamic range, at standard room temperature.
At the turbine exit, since it's just a single substance in gaseous phase, it means it will have less moisture content.
Thus, the correct answer is;the moisture content at turbine exit will decrease
2.31 ft/psig
1.98 psig would equalize feet of head 4’7”
4.583/2.31 = 1.98. .583 is 7”/12”
So round off to 2.0 psig to get steady stream of bubbles
Answer:
26.1 ft/s²
Explanation:
See attached pictures for detailed explanation.
Answer:
When the circuit switch is off, no electricity will flow and then the circuit is called an open circuit. Electricity will not flow in open circuit.
Answer:
44.59°c
Explanation:
Given data :
Total pressure = 105 kpa
complete combustion
A) Determine air-fuel ratio
A-F = 
N = number of mole
m = molar mass
A-F =
= 22.2 kg air/fuel
hence the ratio of Fuel-air = 1 : 22.2
B) Determine the temperature at which water vapor in the products start condensing
First we determine the partial pressure of water vapor before using the steam table to determine the corresponding saturation temp
partial pressure of water vapor
Pv = 
N watervapor ( number of mole of water vapor ) = 3
N pro ( total number of mole of product = 3 + 3 + 2.25 + 25.28 = 33.53 kmol
Pro = 105
hence Pv = ( 3/33.53 ) * 105 = 9.39kPa
from the steam pressure table the corresponding saturation temperature to 9.39kPa = 44.59° c
Temperature at which condensing will start = 44.59°c
An equation showing the products of propylene with their mole numbers is attached below